All categories

3 years ago

What is the area of this trapezoid?

Mathematics

1 answer:

kolezko [41]3 years ago

5 0

Answer:

are of trapezoid =1/2×height(a+b)

Step-by-step explanation:

A=1/2×8(10+20)

=4×30

=120cm*

You might be interested in

The graph shows the location of point P and point R. Point R is on the y-axis and has the same y-coordinate as point P. Point Q

Mumz [18]

Answer:

n = 5

Step-by-step explanation:

Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

$\sqrt{ {( n - n}) ^{2} + {( 3- ( - 2) })^{2} }$

$= > \sqrt{ {(3 + 2)}^{2} } = \sqrt{ {5}^{2} } = 5$

Distance between P & R =

$\sqrt{ {(n - 0)}^{2} + {(3 - 3)}^{2} }$

$= > \sqrt{ {n}^{2} } = n$

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

$n = 5$

8 0

2 years ago

3. What is the converse of the following statement?If M is the midpoint of line segment PQ, then line segment PM is congruent to

Len [333]

Solution

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Define the converse of a statement

The converse of a statement is formed by switching the hypothesis and the conclusion.

STEP 2: break down the given statements

Hypothesis: If M is the midpoint of line segment PQ,

Conclusion: line segment PM is congruent to line segment QM

STEP 3: Switch the two statements

Hence, the answer is given as:

If line segment PM is congruent to line segment QM, then M is the midpoint of line segment PQ,

6 0

1 year ago

Plz help simplify 8/10

Free_Kalibri [48]

$\frac{8}{10}$ → $\frac{4}{5}$

8 and 10 can both be divided by 2. So, 8 ÷ 2 is 4 and 10 ÷ 2 is 5.

Hope this helps :)

3 0

3 years ago

Read 2 more answers

Which point lies on the circle represented by the equation (x+5) + (y-9) = 8

olga_2 [115]

Answer:

(-5,9+√8)

Step-by-step explanation:

There are two ways in which you can find a point that lies in the circle. One of them is to do y the subject of the formula, and another one is to determine the center of the circumference, and with the information of the radius, you can sum this value upward or downward.

the general equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$