solve. 1/3/4+ 7/8 A. 2/1/4 B. 2/5/8 C. 2/3/8 D. 3/1/2

irina1246 [14]

Turn off the faucet if not in use
Take shorter showers
Water your plants only when it needs it
Don’t throw trash on the sea

6 0

3 years ago

What is 150 percent as a mixed number

scZoUnD [109]

150% as a mixed number is 1.5 which = 1 1/2

6 0

3 years ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Which facts could be applied to simplify this expression? Check all that apply.

lisov135 [29]

The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.

C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.

D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.

stay safe!! wash ur hands and wear a mask :D

3 0

2 years ago

Alaina has 7 in her bank account and earns 6 each day . joel has 48 in his banck account and earn 8 earch day in how many days w

Elis [28]

Answer:

I think you wrote something wrong.

Step-by-step explanation:

If Alaina has $7 in her bank account and Joel had $48 in his Joel already has more then Alaina but I will attempt to teach you how to solve these types of problems.

for this example I'm giving Alaina 79 dollars.

First we know were starting with 79 dollars and increasing 6 dollars each day so the equation for this is; y = 6x + 79 that is Alaina's equation.

For Joel our equation will be; y = 8x + 48.

Since they already have 79 and 48 dollars in their bank we put those as our B in the equation cause they are our y-intercepts. (Y = mx + b) Next we know their increasing by 6 and 8 dollars a day so we make those our m. Once we have these equations we can plot them and see where the lines meet. (thats our answer) I plotted them on desmos graphing calculator.

They crossed at (15.5, 172) Which means it will take 16 days for Joel to catch up they will both have 172 dollars in the bank account on the 16th day.

Hope this helps!

8 0

2 years ago