36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)
Solution:
Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes
P(old,even) = 9/36 =1/4 = 0.25
Answer:
All the GCFs look good! Here's the simplified fractions:
Step-by-step explanation:
1. 2/3
2. 3/4
3. 3/7
4. 3/16
5. 27/29
6. 4/11
7. 2/11
Simply divide the numerator by the GCF to find the simplified numerator, and the denominator by that same GCF to find the simplified denominator!
