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dimulka [17.4K]
3 years ago
6

Solve using substitution y=1/2x x+4y=18

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

The solution set is (6,3)

Step-by-step explanation:

Begin by multiplying equation 1 by 2. You'll see why in a moment

2y = 2*(1/2) x

2y = x

Substitute this value into equation 2.

2y + 4y = 18                  Combine like terms on the left

6y = 18                          Divide both sides by 6

6y/6 = 18/6                    Do the division

y = 3

To solve for x just use the top equation

y = 1/2x

3 = 1/2x                          Multiply by 2

3*2 = x

x = 6


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motikmotik
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5 0
4 years ago
Solve for the letter A. ab+d=c
Eddi Din [679]

Answer:

a=c/b-d/b

Step-by-step explanation:

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3 years ago
Read 2 more answers
#1. Factor the expression. 4g^2+21g-49
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1. You want to find factors of 4×(-49) that add to 21. Those would be +28 and -7. Replacing the term 21g with the sum 28g -7g, we get an expression that can be factored by grouping.

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... = 4g(g +7) -7(g +7) = (4g-7)(g+7)

2. After you factor out 5, you have 5(64y² -16y -15). As in the previous problem, you're looking for factors of 64×(-15) = -960 that sum to -16. There are 14 factor pairs of 960, so it can take a little bit of effort to find the right pair. That pair is -40 and 24. As in the previous problem you replace the term -16y with the sum -40y +24y and factor by grouping.

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... = 5(8y +3)(8y -5)

3. False. It is perhaps easiest to check this by multiplying out the offered factors. Doing that gives you 36k² -36k +8k -8. The collected k terms add to -28k, not -44k.

4 0
4 years ago
An oval track is made by erecting semicircles on each end of a 44 m by 88 m rectangle. Find the length of the track and the area
Dmitry_Shevchenko [17]

Answer:

The length of the track is 247 m.

The area enclosed by the track is  5391 . 76 sq m.

Step-by-step explanation:

The length of the rectangle  = 88 m

The width of the rectangle  =  44 m

Now, as we know the semicircles are at the end of rectangular track.

So, the diameter of semicircles = Width of the rectangle

⇒ The diameter of the semi circle  = 44 m

⇒Radius of the semi circle  = 44/2 = 22 m

TOTAL LENGTH OF TRACK  

= 2 ( Length of rectangle)  + 2 (Circumference of 1 semicircle)

= 2 x (88 m)  + 2 (\frac{2\pi r}{2})

= 176 m + 2 (3.14)(22 m)  = 176 + 71.08 =  247 m

Hence, the length of the track is 247 m

TOTAL AREA OF TRACK  

= (Area of rectangle)  + 2 (Area of 1 semicircle)

= (Length x Width)  +    2 (\frac{\pi r^2}{2})

=  (44  m x 88 m) +  (3.14)(22 m)(22 m)   = (3872  + 1519.76) sq m

=  5391 . 76 sq m

Hence, the area enclosed by the track is  5391 . 76 sq m.

7 0
3 years ago
Games Galore Super Store buys the latest video game at a wholesale price of $30.00. The markup rate at Game's Galore Super Store
marishachu [46]

Answer:

<h2>$42</h2>

Step-by-step explanation:

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therefore the sale price will be the markup rate plus the initial price

<em>Hence the you will have to pay 12+30=$42</em>

6 0
3 years ago
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