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4 years ago

What is the answer to this question?

Mathematics

1 answer:

Aloiza [94]4 years ago

8 0

Your graph is that blue line. Note that this horizontal line passes thru y=1.
The equation of the graph is thus y = 1.

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What is the value of X in the isosceles trapezoid below?

Nana76 [90]

Answer:

Step-by-step explanation:

Remember that in a isosceles trapezoid, its angles on the base are always congruent.

Also, we know by definition that the sum of interior angles of a trapezoid is equal to 360°, so

$2(2x)+2(10x+24)=360\\4x+20x+48=360\\24x=360-48\\x=\frac{312}{24}\\ x=13$

Therefore, the right answer is D.

3 0

3 years ago

Will mark brainliest!!!

gizmo_the_mogwai [7]

First, simplify the equation to slope intercept form to find the slope;

2x+3y=4
3y=4-2x
y=(-2x+4)/3

The slopes of parallel lines are the same, therefore, the slope of the second line would also be -2/3

Write out the slope intercept form with the information we know and input the coordinates of the point;

y=mx+c
-4=(-2/3)(1)+c
-4+(2/3)=c
(-12/3)+(2/3)=c
-10/3=c

Therefore, the final equation is y=-2/3x-10/3

Hope I helped :)

7 0

4 years ago

The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 17 minute

Arturiano [62]

Answer:

P(X>5) = 0.857

Step-by-step explanation:

Let X $\sim$ uniform(3.17)

$f(x) = \dfrac{1}{17-3} ; \ \ \ 3 \le x \le 17$

The required probability that it will take Isabella more than 5 minutes to wait for the bus can be computed as:

$P(X > 5) = \int ^{17}_{5} f(x) \ dx$

$P(X > 5) = \int ^{17}_{5} \dfrac{1}{17-3} \ dx$

$P(X > 5) =\dfrac{1}{14} \Big [x \Big ] ^{17}_{5}$

$P(X > 5) =\dfrac{1}{14} [17-5]$

$P(X > 5) =\dfrac{12}{14}$

P(X>5) = 0.857

6 0

3 years ago

two minutes after a diver enters the water,he has descended 52 feet.After5 minutes, he has decended 130 feet.At what rate is the

ICE Princess25 [194]

Rate: 26 feet per minute.

3 0

3 years ago

the numerator of a fraction x/y is 2 less than the denominator. If 3 is added to both the numerator and denominator, then the su

Mashutka [201]

Answer:

Step-by-step explanation:

Fraction :x/y

numerator x = y - 2

Now the fraction can be written as: (y-2)/y

3 is added to both denominator and numerator.

After adding 3, the new fraction = $\frac{y-2 +3 }{y + 3 } = \frac{y+ 1 }{y +3}$

The sum of the new fraction and the original fraction is 53/35

$\frac{y+1}{y+3} + \frac{y-2}{y} = \frac{53}{35}\\\\\frac{(y+1)*y}{(y+3)*y}+\frac{(y-2)*(y+3)}{y(y+3)}=\frac{53}{35}\\\\\frac{y^{2}+y}{y^{2}+3y}+\frac{y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{y^{2}+y+y^{2}+y-6}{y^{2}+3y}=\frac{53}{35}\\\\\frac{2y^{2} + 2y - 6}{y^{2}+3y}=\frac{53}{35}\\\\$

35*(2y² + 2y - 6) = 53 *(y² + 3y)

35*2y² + 2y * 35 - 6*35 = 53 *y² + 53*3y

70y² + 70y - 210 = 53y² + 159y

70y² + 70y - 210 - 53y² - 159y = 0

70y² - 53y² + 70y - 159y - 210 = 0

17y² - 89y - 210 = 0

6 0

3 years ago

Read 2 more answers