Twelve flags are evenly spaced around a running track. Ryan started running at the first flag and took 30 seconds to reach the s
ixth flag. How many seconds did it take Ryan, running at a constant rate, to reach the nth flag for the mth time?
1 answer:
Answer:
Ryan takes 6n+36m -42 seconds to reach the nth flag for the mth time.
Step-by-step explanation:
It takes Ryan to run from 1st to 6th flag in 30 seconds, so it takes him
30 * 6/3 = 36 seconds to make one complete round.
or it takes 6 seconds to run from one flat to the next.
To reach the nth flag (n=1,2,3,4,5, or 6)
Ryan takes 6(n-1) seconds.
To reach it the mth times, he needs to add 36(m-1) seconds.
So time it takes Ryan to reach the nth flag for the mth time takes
6(n-1) + 36(m-1)
= 6n - 6 + 36m - 36
= 6n+36m -42 seconds
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Answer:
9
Step-by-step explanation:
The diagram showing the three pieces of paper of three digit in which two of the letters were covered can be seen below.
From the diagram; we have;
243 , 1_7 , _26
Assuming the covered digits are _
The sum is 826.
i.e
243 + 1_7 + _26 = 826
The objective is to determine the sum of the two unknown digits
So; we need to think about what number can we add put in 1_7 to determine the covered digit in _26
From ; 1_7 , we have the choice to pick from 0 - 9
Assuming the covered digit is 0; let's check if we are right
So; 243 + 1<u>0</u>7 + _26 = 826
350 + _26 = 826
_26 = 826 - 350
_26 = 476
So; the covered digit is in the position of 4 , but it doesn't tally together
i.e 426 is not the same as 476, which makes our assumption to be wrong.
Let consider the covered digit to be 5 for example.
So; 243 + 1<u>5</u>7 + _26 = 826
400 + _26 = 826
_26 = 826 - 400
_26 = 426
The covered digit is in the position of 4
SO;
<u>4</u>26 = 426
Here , our assumption is right.
As such , the covered digits are 5 and 4
The sum of the two covered digits are = 5 + 4 = 9
