All categories

3 years ago

The radius of a cylindrical construction pipe is 3.5 ft. If the pipe is 39ft long, what is its volume?

Mathematics

1 answer:

fomenos3 years ago

3 0

Answer:

1500 ft

Step-by-step explanation:

Volume of a cylinder is $\pi*r^{2}*h$

h is the height, r is the radius of a circular cross section.

Plugging this in: $3.14 * 3.5^{2} * 39 = ~1500$

You might be interested in

Liam rented a pedal board for 5.5 hours and paid a total of $93.75. What is an equation in point-slope form that

ExtremeBDS [4]

Answer: if y is the total cost of the rental, then y-93.75=12.5(x-5.5) models the cost of renting a pedal board for x hours. liam should rewrite the equation from the previous step so that y is isolated on one side. the constant on the other side is then the service fee.

Step-by-step explanation:

yeah that’s all

6 0

4 years ago

William just purchased a residential investment property for $225,000. William is 60, married, and will not occupy the property.

vovangra [49]

No, because he has to reside on the property to qualify for a homestead exemption.

5 0

3 years ago

Angles ∠123 and ∠423 share a ray, what is the ray called?

Jet001 [13]

Answer:

Ray 23

Step-by-step explanation:

8 0

3 years ago

Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .

anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

We need to begin with the definition of tangent:

$tan (x) =\frac{sin(x)}{cos(x)}$

So we can replace into our formula and we got:

$tan(x-y) = \frac{sin(x-y)}{cos(x-y)}$ (1)

We have the following identities useful for this case:

$sin(a-b) = sin(a) cos(b) - sin(b) cos(a)$

$cos(a-b) = cos(a) cos(b) + sin (a) sin(b)$

If we apply the identities into our equation (1) we got:

$tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}$ (2)

Now we can divide the numerator and denominato from expression (2) by $\frac{1}{cos(x) cos(y)}$ and we got this:

$tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}$

And simplifying we got:

$tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}$

And this identity is satisfied for all:

$(x-y) \neq \frac{\pi}{2} +n\pi$

8 0

3 years ago

Does this graph represent a function?Why or why not?

cestrela7 [59]

No, it does not have a straight line. (A)

4 0

4 years ago

Read 2 more answers