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1 year ago

12

to set up a model linear equation to fit real world applications, what should always be the first step?

2 answers:

Brilliant_brown [7]1 year ago

5 0

Answer:

to setup the model linear equation to fit a real world application we must first determine the non quantities and the find the unknown quality as a variable can be begin to interview to the voice as mathematical expressions using mathematical symbols

solmaris [256]1 year ago

3 0

Answer:

Define the variables.

Step-by-step explanation:

Define the variables, then set up the equations, and finally solve the system using graphing, substitution, or elimination method.

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Help Fast Show WORK and. NO links <br> 5f = -75 check your solutio\

pantera1 [17]

Answer:

f= -15

Step-by-step explanation:

u just have to divide

-75/5= -15 so f equal -15

3 0

2 years ago

Read 2 more answers

Help again! Just these last 3 questions. I don't wanna beg for answers, but I need help thank you. This assis due in a few minut

lana [24]

Answer:

Question 4: 20 + 6 + 6 + 12 + 16 = 60 $yd^{2}$

Question 5: 144 + 90 + 90 + 48 + 48 = 420 $m^{2}$

Question 6: 78.28 + 78.28 + 88.58 + 27.09 + 27.09 = 299.32 $ft^{2}$

Step-by-step explanation:

Hope this helps!

6 0

2 years ago

Math Help? 20 Points

Pachacha [2.7K]

V= LWH so 3.75cm^3 or 3 (3/4)

Multiply those three sides and it comes out to 3.75

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2 years ago

What is the product?<br><br> (5r − 4)(r2 − 6r + 4)

maxonik [38]

Answer:

1r

Step-by-step explanation:

(5r-4)(2r-6r+4)

1(5r-4)+1(2r-6r+4)

5r-4+2r-6r+4

5r+2r-6=1r

1r-4+4

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1 year ago

Consider the following statement. If r is any rational number and s is any irrational number, then r s is irrational. (a) Which

olganol [36]

Answer:

(a) If r is any rational number and s is any irrational number, then r/s is rational

(b) The statement is false when r is 0

Step-by-step explanation:

Given

$r \to$ rational number

$s \to$ irrational number

$\frac{r}{s} \to$ irrational number

Solving (a): The negation

To get the negation of a statement, we only need to negate the end result

In other words, the number type of r and s will remain the same, but r/s will be negated.

So, the negation is:

$r \to$ rational number

$s \to$ irrational number

$\frac{r}{s} \to$ rational number

Solving (b): When r/s is irrational is false

Given that:

$\frac{r}{s} \to$ irrational number

Set r to 0

So:

$\frac{r}{s} = \frac{0}{s}$

$\frac{r}{s} = 0$ -- rational

<em>Hence, the statement is false when r is 0</em>

8 0

2 years ago