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barxatty [35]
3 years ago
7

Subtract these polynomials. (3x2 – 2x + 5) – (x2 + 3) =

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

D. 2x^2 - 2x + 2

Step-by-step explanation:

(3x2 – 2x + 5) – (x2 + 3) add or subtract like terms

3x^2 - x^2 - 2x - 3 + 5 = 2x^2 - 2x + 2

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Find the surface area of the cylinder
STatiana [176]
<h2><u>Solution</u>:-</h2>

• Surface area of a cylinder = 2πr(r + h) sq. units.

In the above diagram,

Radius (r) of the cylinder = 13 cm.

Height (h) of the cylinder = 39 cm.

<h3>• Taking value of π = 3.14</h3>

Hence, Surface area of the cylinder = 2 × 3.14 × 13(13 + 39)

Surface area of the cylinder = (81.64 × 52) cm²

Surface area of the cylinder = 4245.28 cm²

The surface area of the cylinder is <u>4</u><u>2</u><u>4</u><u>5</u><u>.</u><u>2</u><u>8</u><u> </u><u>cm²</u>. [Answer]

6 0
3 years ago
The larger of two numbers is four more than the smaller number.If the sum of the numbers is 61,find the numbers
sergij07 [2.7K]

Answer:

<u>28.5 and 32.5</u>

Step-by-step explanation:

<em>create an equation to solve:</em>

x + (x+4) =61

2x + 4 = 61 combine like terms

2x = 57 subtract 4 from both sides

x = 28.5 divide 2 from both sides

28.5 is the smaller number

the larger number is 4 more so:

28.5 + 4 = 32.5

32.5 is the larger number

check your work:

28.5 + 32.5 = 61

6 0
3 years ago
A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct
KatRina [158]
<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

          Perimeter=2(L+\sqrt{100-L^2})

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

10=\sqrt{L^2+W^2}

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

W=\sqrt{100-L^2}

Now, we know that the Perimeter of a rectangle is given by:

Perimeter=2(L+W)

Here we have:

Perimeter=2(L+\sqrt{100-L^2})

7 0
3 years ago
Translate to an algebraic expression: 15 less than six times a number, y.
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Answer:

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Step-by-step explanation:

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