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zalisa [80]
3 years ago
13

Here's the deal. I give you a question, you give me an answer. I give you points and Brainliest if possible. You use the points

for questions. The question will be below.

Mathematics
1 answer:
olga55 [171]3 years ago
5 0

Answer:

f(x) = -(x-3)^2 + 4

Step-by-step explanation:

(h; k) are the coordinates of the vertex.

On the graph are (3, 4), therefore we have:

f(x) = a(x-3)^2 + 4

We have the x- intercept (1,0) -> x=1; y=0.

Substitute them into the equation:

0 = a(1 - 3)^2 + 4

0 = a(-2)^2 + 4

4a + 4 = 0 | -4

4a = -4   |-4

a = -1

So, we have the answer:

f(x) = -(x-3)^2 + 4

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Doss [256]

Answer:

Step-by-step explanation:

For any prism or cylinder for that matter, you can find the volume by multiplying the area of the base times the height.  So this problem just becomes simple algebra.

B * h = V

25 * h = 80

h = 80/25

h = 3.2

If you don't get why it's the area of the base let me know and I can try to explain it.  

4 0
3 years ago
find the sum ofthe angle measure in each regular polygon. Then find the measure of each angle. Show work please I'm so bad at th
Tems11 [23]
For every side you just add 90 to your equation. so #4 would be 360-125-125-55=(55)
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A text book cost 65.49$ before tax. the tax on the textbook is 6.5%.what is the total cost of the textbook.
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6 0
3 years ago
M_6 is (2x - 5)º and m_8 is (x + 5)º.<br> What is m 3?
oksano4ka [1.4K]

m_3 is (7x-4)°

Step-by-step explanation:

which is that m_3 is(7x -4)°.

3 0
4 years ago
This Question: 1 pt
zhenek [66]

\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

Angles forming linear pair are :

\mathrm{\angle EFG  \:  \: and \:  \:   \angle GFH}

And we know, they are supplymentary

  • \mathrm{\angle EFG  \:   +  \:   \angle GFH}  = 180 \degree
  • 3n +1 9 \degree+ 2n + 36\degree = 180 \degree
  • 5n + 55\degree = 180\degree
  • 5n = 125\degree
  • n = 25\degree

So, the measures of the given angles are :

  • \mathrm{\angle EFG } = 3n + 19
  • \mathrm{ \angle EFG = (3  \times 25\degree)  + 19}
  • \mathrm{ \angle EFG = 75 \degree+ 19\degree}
  • \mathrm{ \angle EFG = 94\degree}

And

  • \mathrm{ \angle GFH = 2n + 36}
  • \mathrm{ \angle  GFH = (2 \times 25\degree) + 36\degree}
  • \mathrm{ \angle GFH = 50\degree + 36\degree}
  • \mathrm{ \angle GFH = 86\degree }

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

6 0
3 years ago
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