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Anna71 [15]
3 years ago
5

carter lives on a street where all the house numbers are multiples of 6. Name two possible house numbers between 601 and 650. ex

plain
Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer: The answer is 606 and 612.


Step-by-step explanation:  Given that Carter lives on a street where all the house numbers are multiples of 6. We are given to name any two possible house numbers between 601 and 650.

The numbers lying between 601 and 650 are

602, 603, 604, 605, . . . ,648, 649.

And the numbers among these which are multiples of 6 are

606, 612, 618, 624, 630, 636, 642, 648.

So, any two of these eight numbers can be possible.

Thus, the numbers are 606 and 650.

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a ladder leans against the sufe of a house. the angle of elevation of the ladder is 70 degrees when the bottom of the ladder is
nekit [7.7K]

Answer:

≈ 35.1 ft

Step-by-step explanation:

The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°

Using the cosine ratio, with l being the length of the ladder.

cos70° = \frac{adjacent}{hypotenuse} = \frac{12}{l} ( multiply both sides by l )

l × cos70° = 12 ( divide both sides by cos70° )

l = \frac{12}{cos70} ≈ 35.1 ( to the nearest tenth )

The ladder is approx 35.1 ft long

4 0
3 years ago
What's 1/6 divided by 3
erma4kov [3.2K]

Answer:

1/18

Step-by-step explanation:

1/6 * 1/3

1 *1 = 1

6 * 3 = 18

1/18

5 0
3 years ago
Read 2 more answers
The quotient, of the product of 25 and an unknown number, and 45 is -65.
Vsevolod [243]
25x/45=-65
25x=2925
x=117

I wasn't sure if you wanted a solution
8 0
3 years ago
If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
You want to rent a television. Company A charges $25 per week plus a one-time fee of $52. Company B charges $37 per week plus a
RUDIKE [14]
52+25=77+25=102+25=127
16+36=53+37=90+37=127
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