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3 years ago

The sum of two numbers is 23. One number is 9 more than the other. Find the numbers.

Mathematics

1 answer:

forsale [732]3 years ago

5 0

Answer:

the two numbers i think are 16 and 7.

Step-by-step explanation:

this is bc 16 - 7 is 9, and 16 + 7 is 23

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15x+100=82 (has pic)

aksik [14]

15x+100=28
x=-6/5
The answer is -6/5

5 0

3 years ago

Read 2 more answers

If an arrow is shot upward on Mars with a speed of 68 m/s, its height in meters t seconds later is given by

Talja [164]

Answer:

(a) dy/dt = 68 - 3.72t

(b) 64.28m/s

Step-by-step explanation:

Given y = 68t - 1.86t²

Average Speed is rate of chance of distance with respect to time. Written as dy/dt

To obtain dy/dt, we differentiate y with respect to t, doing that, we have

dy/dt = 68 - 2(1.86)t

= 68 - 3.72t

(a) dy/dt = 68 - 3.72t

(b) To estimate the speed when t = 1, we substitute t = 1 in dy/dt .

dy/dt at t = 1 is

68 - 3.72(1)

= 68 - 3.72

= 64.28

The speed at t = 1 is 64.28m/s

6 0

3 years ago

Given that tan^2 theta=3/8,what is the value of sec theta?

algol [13]

Answer:

The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = $\frac{3}{8}$

Or, tanФ = $\sqrt{\frac{3}{8} }$

∵ tanФ = $\frac{Perpendicular}{Base}$

So, $\frac{Perpendicular}{Base}$ = $\sqrt{\frac{3}{8} }$

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( $\sqrt{3}$ )² + ( $\sqrt{8}$ )²

Or, Hypotenuse² = 3 + 8 = 11

Or, Hypotenuse = ( $\sqrt{11}$ )

Now SecФ = $\frac{Hypotenuse}{Base}$

or, SecФ = $\frac{\sqrt{11}}{\sqrt{8}}$ = $\sqrt{\frac{11}{8} }$

Second Method

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 + tan²Ф

or, Sec²Ф = 1 + $\frac{3}{8}$

Or, Sec²Ф = $\frac{11}{8}$

Or, SecФ = $\pm \sqrt{\frac{11}{8}}$

Hence The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ . Answer

7 0

3 years ago

Read 2 more answers

A customer works into a post office to purchase stamps. she purchases a total of 45 stamps. some of the stamps are 49cent stamps

baherus [9]

Step-by-step explanation:Let number of 49 cents =A

Let number of 33 cents=B

A+B=45 equation 1

1 $=100 cents

49 cents =.49 dollar

33 cents=.33 dollar

so .49A+.33B=17.89 equation 2

Add equation 1 and equation 2

since these are simultaneous equations

.49A+.33B=17.89

A+ B=45

so divide equation 2 by 100 we get

49A+33B=1789

A+B =45 multiply equation 1 by 33 on both the sides we get

33A+33B=1485 equation 3

so subtract equation 3 from equation 2 we get

49A+33B=1789 equation 2

33A+33B=1485 equation 3

16A+0 =304

16A=304

A=304/16

A=19

putting nalue of A in equation 1 we get

A+B=45

19+B=45

B=45-19

B=26

so number of 49 cent stamps are 19

and number of 33 cent stamps are 26

5 0

3 years ago

A state vector X for a four-state Markov chain is such that the system is four times as likely to be in state 2 as in 4, is not

GREYUIT [131]

All the components in the state vector need to sum to 1. You're given that component corresponding to state 1 is 0.2, and that the component for state 3 is 0.

That leaves states 2 and 4, for which you're told that the component for state 2 is four times as large. If $x_i$ is the component for state $i$ , then you have

$x_1+x_2+x_3+x_4=1\iff 0.2+4x_4+0+x_4=1\implies5x_4=0.8\implies x_4=0.16$

which means $x_2=4x_4=0.64$ . So the state vector is $\mathbf x=(0.2,0.64,0,0.16)$ .

8 0

3 years ago