Answer:
It can be a really good approach to use a local solver using the min conflicts heuristic in solving sudoku problems. It will work better actually. In this process, the value chosen is the value with the minimum conflicts. This is the general way a normal person would also tackle this problem. By this approach, if we keep taking the values with minimum conflicts the sudoku puzzle can be solved with a better performance.
Explanation:
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believes that the average individual does not need a smart phone
<span>firivolous mean not serious, light, unimportant.</span>
Answer and Explanation:
Multiple-line comments :
Advantage :In the event that we need to remark out of zone of the given program , we can utilize it.
Disadvantage : In numerous line results are in reduced unwavering quality. It stretches out the remark as far as possible of the following comment.For least difficult approach to unintentionally leave off the last delimiter, which successfully expelling code from the program.
Single Line Comments :
Advantage :In the event that you need to close all the delimiter before close the program we utilize this kind of remarks.
Disadvantage : It put more burden on your program .It repeated on every line of a block of comments
Answer:
answer:
#include <iostream>
#include<list>
using namespace std;
bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;
l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";
/*Display the list*/
cout<<endl; return 0;
}
Answer:
the answer is going to be printer
