The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
It’s hz and bandwidth, 5ghz is better then a 2.5ghz but the wavelength is more condensed so it won’t travel so far so the 5ghz will be faster but the 2.5ghz will go further.
Answer:
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have 
bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be .
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to 
.
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>
➷ It would be D. I don't really see how the plug itself is a cause of electrical accidents.
<h3><u>✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
no it is not but u will need a ethernet cord
