A hot air balloon descended 99.6 meters in 12 seconds. What was the balloon's average rate of descent in meters per second?

Mathematics

2 answers:

bagirrra123 [75]2 years ago

5 0

99.6 divided by 12 is 8.3 so the answer is 8.3

maks197457 [2]2 years ago

5 0

Answer: 8.3 meters per second.

Step-by-step explanation:

Given : A hot air balloon descended 99.6 meters in 12 seconds.

then, the average rate of descent is given by :-

$\text{Average rate of descent}=\dfrac{\text{\text{Distance descended }}}{\text{Time}}\\\\\Rightarrow\ \text{Average rate of descent}=\dfrac{99.6}{12}\\\\\Rightarrow\ \text{Average rate of descent}=8.3$

Therefore, the balloon's average rate of descent in meters per second = 8.3 meters per second.

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Step-by-step explanation:

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Analyzing option A)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Putting $x = 1$ in the function

$f\left(1\right)=\:\left(\frac{1}{10}\right)^1$

$f\left(1\right)=\:\left\frac{1}{10}\right$

So, it is TRUE that when $x = 1$ then the out put will be $f\left(1\right)=\:\left\frac{1}{10}\right$

Therefore, the statement that '' The graph contains $\left(1,\:\frac{1}{10}\right)$ '' is TRUE.

Analyzing option B)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The range of the function is the set of values of the dependent variable for which a function is defined.

$\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k$

$k=0$

$f\left(x\right)>0$

Thus,

$\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}$