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tigry1 [53]
3 years ago
14

Let f(x)=x^2+2x+3 . What is the average rate of change for the quadratic function from x=−2 to x = 5?

Mathematics
1 answer:
miskamm [114]3 years ago
5 0
To find the average rate of change of  given function f(x) on a given interval (a,b):

Find f(b)-f(a), b-a, and then divide your result for f(b)-f(a) by your result for b-a:


f(b) - f(a)
------------
    b-a

Here your function is f(x) = x^2 - 2x + 3.  Substituting b=5 and a=-2,
f(5) = 5^2 -2(5)+3 =?                          and f(-2) = (-2)^2 - 2(-2) + 3 = ?


Calculate           f(5) - [ f(-2) ]
                         ------------------ using your results, above.
                              5 - [-2]

Your answer to this, if done correctly, is the "average rate of change of the function f(x) = x^2+2x+3 on the interval [-2,5]."
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Answer:

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Step-by-step explanation:

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Louis has three more quarters than dimes for a total of $1.80. What equation can you use to determine how many dimes,x, in his p
elixir [45]

0.10x + 0.25(x + 3) = 1.80

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Lines ab and cd are parallel. If MN is 70° then what is my
fgiga [73]
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Please help!!!!! it's a word problem and I don't understand how to do it at all
andre [41]
7We can see that line NM = JK so NM also equals 10.
We know NL = 23 and NM = 10 therefore, ML = NL -NM  ML = 23 -13
ML = 10
The last thing to solve is the length of KL
KL = ML / sine 34
KL = 10 / 0.55919
KL = 17.9

Total fence length required = JK + KL + NL =
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8 0
3 years ago
Use the following function to find the value of each operation.
Murljashka [212]
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>

w(f(m(2))) = 593

<h3>Step-by-step explanation:</h3>

We can write how w(f(m(x))) will be defined but that's too much work and it's only useful when we are evaluating w(f(m(x))) with many inputs.

First let's solve for m(2) first. As you read through this answer, you'll get the idea of what I'm doing.

Given:

m(x) = -4x +1

Solving for m(2):

m(2) = -4(2) +1 \\ m(2) = -8 +1 \\ m(2) = -7

Now we can solve for f(m(2)), since m(2) = -7, f(m(2)) = f(-7).

Given:

f(x)=3x-1

Solving for f(-7):

f(-7)=3(-7)-1 \\ f(-7) = -21 -1 \\ f(-7) = -22

Now we are can solve for w(-22). By now you should get the idea why w(f(m(2))) = w(-22).

Given:

w(x) = x^2 -5x -1

Solving for w(-22):

w(-22) = (-22)^2 -5(-22) -1 \\ w(-22) = 484 -5(-22) -1 \\ w(-22) = 484 +110 -1 \\ w(-22) = 593

8 0
3 years ago
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