Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
7/8= 0.875
no rounding necessary
Step-by-step explanation:
(i) From the graph value of x varies -3 to 3 i.e.
and domain in the input values which function can take
So, option (d) is correct.
(ii) option (d) is correct as it represent the function 
. While all the other function does not satisfy the given conditions.
(iii) 
are the parts of solution pair.
(iv) Option (c) and (d) represents the function as each element of the first set has a unique image in the second set.
