Question

Write the equation of the line that passes through the points (-2, -3)

Answer 1

Answer:

$\huge\boxed{y+3=-(x+2)}\\or\\\boxed{y-3=-(x+8)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Put the coordinates of the given point:

(-2, -3); (-8, 3)

$m=\dfrac{3-(-3)}{-8-(-2)}=\dfrac{3+3}{-8+2}=\dfrac{6}{-6}=-1\\\\\text{for}\ (-2;\ -3)\\\\y-(-3)=-1(x-(-2))\\\\y+3=-(x+2)\\\\\text{for}\ (-8;\ 3)\\\\y-3=-1(x-(-8)\\\\y-3=-(x+8)$