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Liono4ka [1.6K]
3 years ago
13

The parent function y = 0.5x is blank across its domain because its base, b, is such that blank

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0

Answer: decreasing; 0 < b < 1

Step-by-step explanation: I got this question on edge

nikitadnepr [17]3 years ago
5 0

Answer:

Decreasing/ 0<b<1

Thank me later ;)

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2. LUIS WANTS TO BUY 2 PENCILS AND 1 NOTEBOOK IN THE STORE. EACH PENCIL COSTS $2 AND THE NOTEBOOK COSTS $6. HOW MUCH MONEY DID L
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Luis spent $10 in total

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Step-by-step explanation:

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picture below

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3 years ago
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

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Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

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P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

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In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

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P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

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3 years ago
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Answer:

undefined

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2 years ago
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