A skier provides what in a landscape photograph of a mountain?

Y'+2y = 5-e^(-4x), y(0)=-11

Anastaziya [24]

Answer:

see attached

Explanation:

A differential equation solver says the exact solution is ...

y = 5/2 -14e^(-2x) +1/2e^(-4x)

The y-values computed by Euler's method will be ...

y = ∆x·y' = 0.1(5 - e^(-4x) -2y)

The attached table performs these computations and compares the result. The "difference" is the approximate value minus the exact value. (When the step size is decreased by a factor of 10, the difference over the same interval is decreased by about that same factor.)

4 0

3 years ago

In this lab, you will create a programmer-defined class and then use it in a Java program. The program should create two Rectang

prohojiy [21]

Answer:

class Rectangle{

//private attributes of length and width

private double givenLength;

private double givenWidth;

// constructor to initialize the length and width

public Rectangle(double length, double width){

givenLength = length;

givenWidth = width;

}

// setter method to set the givenlength

public void setGivenLength(double length){

givenLength = length;

}

// setter method to set the givenWidth

public void setGivenWidth(double width){

givenWidth = width;

}

// getter method to return the givenLength

public double getGivenLength(){

return givenLength;

}

// getter method to return the givenWidth

public double getGivenWidth(){

return givenWidth;

}

// method to calculate area of rectangle using A = L * B

public void calculateArea(){

System.out.println("The area of the rectangle is: " + getGivenLength() * getGivenWidth());

}

// method to calculate perimeter of rectangle using P = 2 * (L + B)

public void calculatePerimeter(){

System.out.println("The perimeter of the rectangle is: " + 2 * (getGivenLength() + getGivenWidth()));

}

public class MyRectangleClassProgram{

public static void main(String args[]){

//rectangle1 object is created

Rectangle rectangle1 = new Rectangle(10.0, 5.0);

//rectangle2 object is created

Rectangle rectangle2 = new Rectangle(7.0, 3.0);

//area for rectangle1 is calculated

rectangle1.calculateArea();

//perimeter for rectangle1 is calculated

rectangle1.calculatePerimeter();

//area for rectangle2 is calculated

rectangle2.calculateArea();

//perimeter for rectangle2 is calculated

rectangle2.calculatePerimeter();

}

Explanation:

Two file is attached: Rectangle.java and MyRectangleClassProgram.java

Download java

java

7 0

3 years ago

A cycle merchant allows 15% discount on the marked price of a bicycle and still he makes a profit

lions [1.4K]

Answer:

The program in Java is as follows:

public class Main{

public static void main(String[] args) {

double discount_percent = 0.15;

double discount_amount = 600;

double profit = 0.20;

double marked_price = discount_amount/discount_percent;

double cost_price = marked_price/(1 + profit);

System.out.println("Marked Price: "+marked_price);

System.out.println("Cost Price: "+cost_price);

}}

Explanation:

For explanation purpose, let

$MP \to$ Marked Price

$\%D \to$ Percentage discount

$D \to$ Discounted amount

$\%P \to$ Percentage Profit

$C \to$ Cost Price

The marked price (i.e. selling price) is calculated discount using:

$MP = \frac{D}{\%D}$

The derived formula of the cost price from percentage profit and Marked Price is:

$C = \frac{M}{1 + \%P * 100}$

So, the explanation is as follows:

The next three lines declare and initialize the given parameters

double discount_percent = 0.15;

double discount_amount = 600;

double profit = 0.20;

Calculate marked price

double marked_price = discount_amount/discount_percent;

Calculate cost price

double cost_price = marked_price/(1 + profit);

Print marked price

System.out.println("Marked Price: "+marked_price);

Print Cost price

System.out.println("Cost Price: "+cost_price);

3 0

3 years ago

Hello everyone. New ppl on Ro.blox? I want to play sometime.

alexira [117]

Answer:

Hello :)

Explanation:

Yesh i play Ro.blox, maybe u or me could friend each other

6 0

3 years ago

Read 2 more answers

Jason is working on a project that requires him to manage a huge amount of data. The spreadsheet he is working on has data relat

Alinara [238K]

A. use split worksheet view to break the worksheet into different visible sections

Explanation:

Jason is working on a project that requires him to manage a huge amount of data. There are numerous instances when a user has to manage a huge amount of data within a single spreadsheet. It will cause trouble for the user to simultaneously access the data from more than one table in the same sheet.

To deal with this problem, Jason can track and compare this data as he works on the spreadsheet by using the split worksheet view to break the worksheet into different visible sections. The different sections provide a better view of the tables and data extraction and manipulation become easy.

6 0

3 years ago