I think it’s 1, 2 and if im wrong im sorry
Answer:
x = int(input("Enter an integer: "))
y = int(input("Enter another integer: "))
if x > y:
for number in range(y+1, x):
print(number, end=" ")
elif y > x:
for number in range(x+1, y):
print(number, end=" ")
else:
print("There are no integers between {} and {}".format(x, y))
Explanation:
*The code is in Python.
Ask the user to enter the two integers, x and y
Since we want our program to run regardless of which entered value is larger, we need to compare the numbers to be able to create the loop that prints the numbers.
Check if x is greater than y. If it is, create a for loop that iterates from y+1 to x-1 and print the numbers
Otherwise, check if y is greater than x. If it is, create a for loop that iterates from x+1 to y-1 and print the numbers
If none of the previous part is executed, print that there are no integers between
Answer:
This question is answered using Java programming language:
public static void print10(String[]arr){
for(int i =0; i<10;i++){
System.out.println(arr[i]);
}
}
Explanation:
This line defines the method
public static void print10(String[]arr){
This iterates from 0 to 9 index of the array. In other words, 1st to 10th
for(int i =0; i<10;i++){
This prints the required output (one on a line)
System.out.println(arr[i]);
}
}
<em>Refer to attachment for the complete program that includes the main method.</em>
Hello, The answer to your question is:-
<em><u>Option </u></em><em><u>"</u></em><em><u>Web </u></em><em><u>2</u></em><em><u>.</u></em><em><u>0</u></em><em><u>"</u></em>
<em><u>Reference and proof</u></em>:-
Web 2.0 refers to websites that emphasize <u>user-generated content</u>, ease of use, participatory culture and interoperability (i.e., compatible with other products, systems, and devices) for end users.
Hope it helps you...
Answered by Benjemin ☺️
✅
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