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Given:
One midsegment of an equilateral triangle.
To find:
The ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths.
Solution:
All sides of an equilateral triangle are same.
Let a be the each side of the equilateral triangle.
Length of the midsegment is equal to the half of the non included side or third side.
The sum of two side is
Now, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is
Therefore, the ratio of the length of one midsegment of an equilateral triangle to the sum of two of its side lengths is 1:4.
106,127,129,132,135,138,140,158
132 + 135 = 267
267/2 = 133.5
Median is 133.5
Answer:
I will not give in answer but will give an example
Step-by-step explanation:
The area of irregular shapes can be determined by dividing the given shape into smaller regular shapes. The area of irregular shapes can be determined by dividing the given shape into smaller regular shapes.
In real life figures are often irregular shapes - a little bit messy. Think of your messy bedroom once more ‐ is it a perfect rectangle?
The trick is to break these figures into shapes that you know well and whose area you know how to find.
1. Find the area of this room:
3- 2 -4 -6 irregular shape
This can be done in two different ways but ill only give one example on how to find an area.
Method #1
Divide the figure into two rectangles and find all missing lengths.
The larger rectangle has an area of
4cm x 7cm = 28cm2
The smaller rectangle has an area of
4cm x 2cm = 8cm2
If we combine these we will find the total area:
28cm2 x 8cm2 = 36cm2
hope this helps :)
