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4 years ago

What is linear equation

Mathematics

1 answer:

Papessa [141]4 years ago

4 0

Answer:

An equation that makes a straight line when it is graphed. Often written in the form y = mx+b. Equation of a Straight Line

Step-by-step explanation:

You might be interested in

Please help :) is it linear, if so model the data with and equation.

Yuki888 [10]

Answer:

The relationship is linear: y -5 = 2 (x+7)

Step-by-step explanation:

While the difference between -7 and -5 / -5 and -3 / -3 and -1 is always 2 teh difference between 5 and 9 / 9 and 13 / 13 and 17 is always 4.

y-5 = -1/2 (x +7)

for x= -7 and y = 5 this is true

for x=-5 and y = 9 this is not true

y + 7 = 1/2 (x-5)

for x= -7 and y = 5 this is not true

y -5 = 2 (x+7)

for x= -7 and y = 5 this is true

for x = -5 and y = 9 this is true

for x = -3 and y = 13 this is true

for x = -1 and y = 17 this is true

8 0

3 years ago

Just to make sure, does this make sense?

Bogdan [553]

Answer:

It makes sense to me but I don't know if anyone else agrees

Step-by-step explanation:

4 0

2 years ago

Find the standard form of the equation for the circle with the following properties.

nataly862011 [7]

Answer:

$(x+6)^2+(y+\frac{7}{6})^2=\frac{49}{36}$

Step-by-step explanation:

So, we know that the center of the circle is at (-6, -7/6).

To find the equation of our circle that is tangent to the x-axis, we just need to find the vertical distance from our center to the x-axis.

Our center is at (-6, -7/6). The vertical distance from this to the x-axis directly above will be (-6, 0).

So, find our distance by subtracting our x-values:

$d=r=0-(-7/6)$

Subtract:

$d=r=7/6$

So, our distance, which is also our radius, will be 7/6.

Now, we can use the standard form for a circle, which is:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Substitute -6 for h, -7/6 for k, and 7/6 for r. This yields:

$(x+6)^2+(y+\frac{7}{6})^2=\frac{49}{36}$

We can confirm by graphing (using a calculator):

7 0

3 years ago

If u show ur work u will get brainliest this is worth 15points if u cant show your work the tell me along with the answer

jenyasd209 [6]

Answer:

The answer is G

Step-by-step explanation:

This is because an expression can't have an equal sign.

like the rest of the answers (F,H, and J) all have an equal word like is or equals.

example

answer F is

6y = 24

The is in the phrase is the equal sign.

Get it?

If you have any questions feel free to ask - Mark

8 0

3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al

Alla [95]

Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:

$\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3$

Then, our options are the following:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}$

For two perpendicular lines it is true that the product of its slopes is:

$m_{1}m_{2}=-1$

$m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}$

According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

$y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!$

Finally, the right answer are:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)$

8 0

3 years ago

Read 2 more answers

What is linear equation​

What is linear equation