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VLD [36.1K]
3 years ago
10

Number 11. It's solving equations containing parentheses and having the variable in both sides.

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0
11.\\\\2(6d+3)=18-3(16-3d)\\\\12d+6=18-48+9d\\\\12d-9d=18-48-6\\\\3d=-36\\\\d=-12
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What is the probability of<br> spinning an A?<br> B<br> B<br> A<br> B<br> C<br> A<br> [?]%<br> C
siniylev [52]

Answer:

25%

Step-by-step explanation:

when we count, we know that there are 8 possible outcomes as to where the spinner will land.

<em>{the following will be assuming each section has an equal chance of being landed on; that the spinner is not weighted}</em>

<em />

We know that two of these 8 possibilities are "A"

This means that A has a 2/8 chance of being landed on

we can simplify 2/8 to 1/4; because they are equivalent ratios/fractions

to calculate percentage, we can follow through with our equation of 1/4

[divide 1 by 4]

1 / 4 = 0.25

We multiply this number by 100 to find percentage,

0.25 × 100 = 25

meaning that A has a 25% chance of being spun

hope this helps!! have a lovely day :)

8 0
2 years ago
Read 2 more answers
-5 divided by 4 =.-12
Pachacha [2.7K]

Answer:

-5 ÷ 4 = -1.25 or 1 \frac{1}{4}

The answer is -1.25

I hope that this helps you! ^‿^

3 0
4 years ago
Read 2 more answers
What is the solution for x in the equation?
Vsevolod [243]

Answer:

Perpendicular ⇒

m = -1/-4 = 1/4

g(x) = (1/4)x + b

3/4 = (1/4)(5) + b

b = -1/2

g(x) = (1/4)x - 1/2

Step-by-step explanation:

3 0
3 years ago
Fill the value of the expression 24 3/5 +4 ×(8 1/5-2)
Julli [10]
First off, we'll convert the mixed fractions to "improper",

\bf \stackrel{mixed}{24\frac{3}{5}}\implies \cfrac{24\cdot 5+3}{5}\implies \stackrel{improper}{\cfrac{123}{5}}&#10;\\\\\\&#10;\stackrel{mixed}{8\frac{1}{5}}\implies \cfrac{8\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{41}{5}}

\bf 24\frac{3}{5}\times \left( 8\frac{1}{5}-2 \right)\implies \cfrac{123}{5}\left( \cfrac{41}{5}-2 \right)\impliedby \mathbb{PEMDAS}&#10;\\\\\\&#10;\cfrac{123}{5}\left( \cfrac{41-10}{5} \right)\implies \cfrac{123}{5}\left( \cfrac{31}{5} \right)&#10;\\\\\\&#10;\cfrac{123\cdot 31}{5\cdot 5}\implies \cfrac{3813}{25}\implies 152\frac{13}{25}
4 0
3 years ago
(14.14) larry reads that 1 out of 6 eggs contains salmonella bacteria. so he never uses more than 5 eggs in cooking. if eggs do
melomori [17]

we know that

The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.

The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.

If the probability that any one egg has 1/6 chance of salmonella

then

the probability that any one egg will not have salmonella = 5/6.

Therefore

for all 5 to not have salmonella


= (5/6)^5 = 3125 / 7776

= 0.401877 = 0.40 to 2 decimal places


REMEMBER this is the probability that NONE have salmonella


Therefore

the probability that at least one does = 1 - 0.40

= 0.60


the answer is

0.60 or 60%

6 0
3 years ago
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