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STatiana [176]
3 years ago
14

Which property of exponents must be used first to solve this expression? (xy^2)^1/3

Mathematics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

The required property of exponent is power of a product property, i.e., (ab)^n=a^nb^n.

Step-by-step explanation:

The given expression is

(xy^2)^{\frac{1}{3}}

To simplify this expression the first property of exponents which is used , is the power of a product property.

According to the power of a product property of exponents

(ab)^n=a^nb^n

Using this property the given expression can be written as

(xy^2)^{\frac{1}{3}}=x^{\frac{1}{3}}(y^2)^{\frac{1}{3}}

Therefore the required property of exponent is power of a product property, i.e., (ab)^n=a^nb^n.

Ratling [72]3 years ago
3 0

(ab)n=anbn......................................

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You randomly survey students about whether they like hamburgers or hot dogs. of 129 students who like hamburgers, 46 like hot do
Ludmilka [50]

 Here is the two-way table and the marginal frequencies in bracket:                          

                                 Like hamburger    do not like hamburger      Total

Like hot dog                    46(0.16)             54 (0.10)                        100(0.36)

Do not like hot dog          83(0.30)           95 (0.34)                        178(0.64)

Total                                 129 (0.46)             149 (0.54)                  278(1)

<h3>What is the two-way table?</h3>

Number of people who like hamburger but do not like hot dog = 129 - 46 = 83

Number of people who do not like hamburger and do not like hot dog = 149 - 54 = 95

Total number of people who like hot dog = 46 + 54 = 100

Total number of people who do not like hot dog = 83 + 95 = 178

Total = 100 + 178 = 278

The marginal frequency can be determined by dividing each number by the total number of people in the survey.

  • marginal frequency of people who like hot dog = 100 / 278 = 0.36
  • marginal frequency of people who do not like hot dog = 178 / 278  = 0.64

To learn more about two way frequency tables, please check: brainly.com/question/27344444

#SPJ1

3 0
2 years ago
Someone please help thanks !
Rama09 [41]

Answer:

sorry vud

Step-by-step explanation:

I don't know

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