All categories

3 years ago

Which property of exponents must be used first to solve this expression? (xy^2)^1/3

Mathematics

2 answers:

snow_lady [41]3 years ago

8 0

Answer:

The required property of exponent is power of a product property, i.e., $(ab)^n=a^nb^n$ .

Step-by-step explanation:

The given expression is

$(xy^2)^{\frac{1}{3}}$

To simplify this expression the first property of exponents which is used , is the power of a product property.

According to the power of a product property of exponents

$(ab)^n=a^nb^n$

Using this property the given expression can be written as

$(xy^2)^{\frac{1}{3}}=x^{\frac{1}{3}}(y^2)^{\frac{1}{3}}$

Therefore the required property of exponent is power of a product property, i.e., $(ab)^n=a^nb^n$ .

Ratling [72]3 years ago

3 0

(ab)n=anbn......................................

You might be interested in

What is the output, or y-value, when you input x = 1 into the function:

Aleksandr [31]

Answer: $y=-6$

Step-by-step explanation:

By definition, a relation is a function if and only if each input value has one and only one output value.

For this exercise it is important to remember that thw "Input values" are the values of the variable "x"and the "Output values" are the values of the variable"y".

In this case you have the following function provided in the exercise:

$y = x^4 - 2x^3 + x^2 + 4x - 10$

Then, to solve this exercise, you need to follow these steps:

Step 1. You have to substitute $x=1$ into the function given.

Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")

You get that this is:

$y = (1)^4 - 2(1)^3 + (1)^2 + 4(1) - 10\\\\y=-6$

3 0

3 years ago

What is the solution to the equation 4w=2/3?

nikdorinn [45]

Answer:

2/12

Step-by-step explanation:

4w=2/3

1/4(4w)=1/4 x 2/3

w=2/12

6 0

3 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

3 years ago

What's the average of 19 from 45

Naya [18.7K]

The average can be calclculated as follows:
average = sum of number/number of numbers
average = (19+45) / 2 = 64/2 = 32

4 0

3 years ago

Read 2 more answers

Use the diagram that awnser the questions.

CaHeK987 [17]

Part A
The first thing we must do in this case is to hide the slopes of each line.
line m:
m = (- 4-3) / (0 - (- 4))
m = -7 / 4
Line n:
n = (- 2-2) / (3-1)
n = -4 / 2
n = -2
Answer:
Lines m and n are not parallel because their slopes are different.

Part B:
We look for the slope of the K line:
k = (1 - (- 3)) / (4 - (- 3))
k = 4/7
We observe that it is true that:
k = -1 / m
Answer:
The lines are perpendicular.

8 0

3 years ago

Read 2 more answers