Find the sum of the first 4 terms
2, -8, 32, -128 are the first 4 terms
<em>2 + (-8) + 32 + ( - 128)</em>
2 + ( - 8) = -6
-6 + 32 = 26
-128 + 26 = -102
-102 is the sum of the first four terms
hope this helps
If , then this translates to the equation
Solve for .
though it is a bit unusual (but not entirely out of the question) to have an irrational base number system.
In case you meant on the right side, then , so that
which at first glance seem like more reasonable choices of base.
We must find UNIQUE combinations because choosing a,b,c,d... is the same as d,c,b,a...etc. For this type of problem you use the "n choose k" formula...
n!/(k!(n-k)!), n=total number of choices available, k=number of choices made..
In this case:
20!/(10!(20-10)!)
20!/(10!*10!)
184756
Answer:
oh I know the answer its r=27
Step-by-step explanation:
I know that it is 27 because 16+24=65 and 65+27 is 180
Answer:
(x + 4)(x + 5)
Step-by-step explanation:
The given equation in the form of polynomial is:
Factorizing the above given equation, we get
Taking x+5 common, we have
which is the required factorised form.
Therefore the factors of the given polynomial are .