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3 years ago

What is the average of 2.34, -2/7, -0.45, and 3/8

Mathematics

1 answer:

Elodia [21]3 years ago

6 0

Answer: 0.49375, or 0.5

Step-by-step explanation: add up 2.34, -0.29, -0.45, and 0.38, which equals 1.975, then divide that by four (since there are 4 numbers) and you get 0.49375

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PLS HELP I WILL MARK BRAINLIEST

tamaranim1 [39]

The green triangle is the rotated image PQR. Point of rotation is (1,-1).

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3 years ago

Read 2 more answers

Rita sells beaded necklaces. Each large necklace sells for $5.40 and each small necklace sells for $5.10 . How much will she ear

ziro4ka [17]

Answer:

$42.90

Step-by-step explanation:

to find how much money selling the large necklaces multiply the amount and how many were sold

5.40*7

$37.80

add the money from the one small necklace that was sold

37.80+5.10

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3 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$

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3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

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3 years ago

Whatcha of the following represent the solution to the given quadratic inequality? y≤-x^2-3x+10?

iren2701 [21]

Answer:

correct do

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2 years ago