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jasenka [17]
3 years ago
8

Hello, I need help with this question, please and thank you.

Mathematics
1 answer:
dangina [55]3 years ago
5 0

Step-by-step explanation:

It appears that given geometrical shape is a HEXA-DECAGON or a 16 sided polygon.

Measure of one interior angle of hexa-decagon can be given as:

\frac{(n - 2) \times 180 \degree}{n}  \\  \\  =   \frac{(16 - 2) \times 180 \degree}{16} \\  \\  =   \frac{14 \times 45 \degree}{4} \\  \\ =   \frac{7 \times 45 \degree}{2} \\  \\  = \frac{315 \degree}{2}  \\  \\  = 157.5\degree \\

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If, in a right triangle, θ = 16 and hypotenuse has length 4, how long is the side adjacent to θ? Round to at least 3 decimal pla
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Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

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