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tigry1 [53]
3 years ago
6

A submarine's position is -325 feet. If it descends 98 feet what is its new position?

Mathematics
1 answer:
Alika [10]3 years ago
6 0

Answer:

Answer is -483

Step-by-step explanation:

hope this helps

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I NEED HELP PLS I WILL GIVE CROWN: Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of
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Let x represents the width of the rectangle,

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Also it is given that the perimeter of the rectangle = 250 feet.

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If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30,  the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.

8 0
3 years ago
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