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2 years ago

There are 454 grams in a pound. Convert 330 grams to ounces.

Mathematics

2 answers:

kap26 [50]2 years ago

6 0

<u>Answer:</u>

Option C. 330 grams in terms of ounce: 11.6 ounce

<u>Solution:</u>

Pound, gram and ounce are the units of mass. The value of one pound in ounce is 16 i.e. 1 pound =16 ounce.

So, to convert 330 grams to ounces initially we have to convert grams to pounds and then it can be converted in terms of ounces.

$1 gram = \frac {16}{454} ounce$

Therefore,

330 grams = $\frac{16\times330}{454}$ ounce

which is $\bold \frac{5280}{454} = 11.62 ounces\bold$

Eddi Din [679]2 years ago

3 0

Answer:

C)11.6

Step-by-step explanation:

330g - oz = 11.64oz

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LenKa [72]

Answer:

(B) (0.396, 1.712)

Step-by-step explanation:

From the information given;

Confidence Interval = 0.95

Significance Level $= 1 - 0.95 = 0.05$

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From the regression coefficient, the estimated value of beta^ = 1.054

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2 years ago

Sue deposited $52 into her bank account, so she currently has $12 in her account. What was her balance before the deposit?

Semenov [28]

Answer:

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Step-by-step explanation:

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3 years ago

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An archaeologist at a dig sets up a coordinate system using string. Two similar artifacts are found one at position (1, 4) and t

myrzilka [38]

Given:

Positions of two artifacts are at points (1, 4) and (5, 2).

To find:

The distance between these two artifacts.

Solution:

Distance formula: The distance between two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, the distance between two points (1, 4) and (5, 2) is

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$d=\sqrt{(4)^2+(-2)^2}$

$d=\sqrt{16+4}$

$d=\sqrt{20}$

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Round to the nearest tenth of a unit.

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Therefore, the distance between two artifacts is 4.5 units.

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2 years ago

write the equation of the line with x-intercept of -4 and y-intercept of 2. Hint:with those intercepts, (-4,0) and (0,2) are poi

Ber [7]

X/(-4)+y/2=0
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3 years ago

I need to know the whole thing please help

aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method Frequency

Public Transport 12

Car 15

Cycle 9

Walk 16

Find the relative frequency of.

The formula used will be: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 43/52

Decimal = 0.827

6 0

2 years ago