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Ulleksa [173]
3 years ago
10

I need help with this problem

Mathematics
2 answers:
Serga [27]3 years ago
6 0
Angles of a triangle is equal to 180
180-52+62=66
angle sum on a straight line is 360
360-66=294
Alja [10]3 years ago
4 0
Its answer choice C would you like me to explain how i worked the problem?
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Two functions are shown below.<br> f(x)=4^x-62<br> g(x)=x^2-2x+5<br><br> evaluate g(-2)+f(3)
algol [13]

Answer:

...

Step-by-step explanation:

5 0
2 years ago
How many positive integers can be expressed ad a product of two or more of the prime numbers 5,7,11,and 13 if no one product is
sertanlavr [38]

Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

How many positive integers can be expressed as a product of two or more of the prime numbers, that means there can be product of two numbers, three number or four numbers.

The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

^4C_2+^4C_3+^4C_4=\frac{4!}{2!2!}+\frac{4!}{3!}+1

^4C_2+^4C_3+^4C_4=6+4+1

^4C_2+^4C_3+^4C_4=11

Hence, 11 positive integers can be expressed.

8 0
3 years ago
In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them
Mariulka [41]

Answer:

<em>Two possible answers below</em>

Step-by-step explanation:

<u>Probability and Sets</u>

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

\displaystyle P=\frac{19}{29}

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

\displaystyle P=\frac{17}{29}

P = 0.59

3 0
3 years ago
Evaluate the expression for a = 5, b = 11, and c = 3. 2a + 2c(b − 5) A. 64 B. 46 C. 54 D. 163
Artemon [7]

2a +2c(b-5)

substitute a=5 b=11 c=3

2(5) +2(3) (11-5)

10+6(6)

10+36

46

Choice B


8 0
2 years ago
Need help with thisss
frozen [14]

9514 1404 393

Answer:

  cos(x) = 0.6

Step-by-step explanation:

First, we need to find UQ.

  UQ = UP·cos(y°) = UP·√(1 -sin²(y°)) = (26 cm)√(1 -25/169) = (26 cm)(12/13)

  UQ = 24 cm

Then TQ is ...

  TQ = 1/3UQ = 1/3(24 cm) = 8 cm

And cos(x°) is ...

  cos(x°) = √(1 -sin²(x)) = √(1 -64/100)

  cos(x°) = 6/10 = 3/5

  cos(x°) = 3/5 = 0.6

7 0
3 years ago
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