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Ahat [919]
3 years ago
12

Solve the following equation for x: z=x^2+wx

Mathematics
1 answer:
Alja [10]3 years ago
4 0
Minus z both sides
0=x^2+wx+z
we can use quadratic formula or manually complete the square
let's use quadratic

for
0=ax^2+bx+c
x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}
given
0=1x^2+wx-z
a=1
b=w
c=-z

x= \frac{-w+/- \sqrt{w^2-4(1)(-z)} }{2(1)}
x= \frac{-w+/- \sqrt{w^2+4z} }{2}

x= \frac{-w+ \sqrt{w^2+4z} }{2} or x= \frac{-w- \sqrt{w^2+4z} }{2}
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