Answer:
position: (-6, -4)
range: 6
Step-by-step explanation:
The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.
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The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Matching parts of the equation, we find ...
h = -6, k = -4, r = √36 = 6.
Answer:
A = (Z-CD - EFG)/B
Step-by-step explanation:
AB + CD + EFG = Z.
Subtract CD and EFG from each side
AB + CD + EFG-CD -EFG = Z-CD - EFG
AB = Z-CD - EFG
Divide each side by B
AB /B = (Z-CD - EFG)/B
A = (Z-CD - EFG)/B
Answer:
105 pi m^2
Step-by-step explanation:
radius squared - radius squared =
(16+3)^2 - 16^2 =
19^2 - 16^2 =
361-256= 105
The answer would be A because line CB is equivalent to ZY tight? And angles Z and C are congruent. We also know that they are congruent by a ASA relationship, <u><em>so then angles Y and B are congruent, the answer is A.</em></u>
First you would start getting the denominators to the same number and you could do this by multiplying 9/10 by 4, and 7/8 by 5 to get the denominators to 40 and when you add the fractions you get 71/40 so the answer would be D. About 2
