Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many combination of random samples of 4 students can be selected?
4 from a set of 12. So
495 combinations of 4 students can be selected.
Answer:
2a+3b
Step-by-step explanation:
There wouldn't be a simplfied answer or solution if you don't have a solution for either a or b or both. And they are not like terms, so you can't add them together.
So the answer is 2a + 3b.
I hope this helps!
Have a great day!
A = 5, -10
B = 1, 8
C = 5, -7
3x+10x+x-2/x+3
14x-2/x+3
7(2x-1)/x+3
Answer:
x ≈ 73.3
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos39° = 
= 
( multiply both sides by x )
x × cos39° = 57 ( divide both sides by cos39° )
x = 
≈ 73.3 ( to the nearest tenth )
