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3 years ago

Can someone please help me

Mathematics

2 answers:

Brrunno [24]3 years ago

6 0

Answer:

S =7

equations: E = 4 and

E = S - 3

Step-by-step explanation:

Let area of Europe = E

Let area of South America = S

then

E = 4

E = S - 3

then S = E + 3 = 4 + 3 = 7

So S = 7

Vladimir [108]3 years ago

3 0

Sorry I don’t know, but I need to answer to get an answer so so sorry

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write the standard form of the equation of the circle for which the endpoints of a diameter are (0,0) and (4,-6)

Elenna [48]

Given:

The endpoints of a diameter are (0,0) and (4,-6).

To find:

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Solution:

The endpoints of a diameter are (0,0) and (4,-6). So, the length of the diameter is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

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Now, radius is half of the diameter.

$r=\dfrac{2\sqrt{13}}{2}$

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Center of the circle is the midpoint of the endpoints of a diameter.

$Center=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Center=\left(\dfrac{0+4}{2},\dfrac{0+(-6)}{2}\right)$

$Center=\left(\dfrac{4}{2},\dfrac{-6}{2}\right)$

$Center=\left(2,-3\right)$

Standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center and r is radius.

The center of the circle is (2,-3) and radius is $\sqrt{13}$ . So,

$(x-2)^2+(y-(-3))^2=(\sqrt{13})^2$

$(x-2)^2+(y+3)^2=13$

Therefore, the standard form of the circle is $(x-2)^2+(y+3)^2=13$ .

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3 years ago

Can someone help me pls

Vladimir79 [104]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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