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DENIUS [597]
3 years ago
11

I need help with this please:/

Mathematics
2 answers:
ser-zykov [4K]3 years ago
7 0
4.5
pi is about 3.14 and root 23 is about 4.8 - the only number between these values is 4.5
Viktor [21]3 years ago
4 0
4.5 is the answer to this!!!
You might be interested in
HELP! Ev evaluate the square root of 16 plus the square root of 29, correct to two decimal places.
Stella [2.4K]

Answer:

\sqrt{16} +\sqrt{29} =9.39

Step-by-step explanation:

\sqrt{16} =4

\sqrt{29} ≅ 5.39

4+5.39=9.39

6 0
3 years ago
Read 2 more answers
Solve for p.<br><br> 13 − 2p = 5<br><br> p =
Naya [18.7K]

Answer:

P = 4

Step-by-step explanation:

2 x 4 is 8

so 13 - 8 = 5

7 0
3 years ago
If the mean of 25, 28, a, 30 and 32 is 27, then find the value of a.
Anna11 [10]

Answer:

a = 20

Step-by-step explanation:

The mean is calculated as

mean = \frac{sum}{count}

          = \frac{25+28+a+30+32}{5}  = \frac{115+a}{5}

Then

\frac{115+a}{5} = 27 ( multiply both sides by 5 to clear the fraction )

115 + a = 135 ( subtract 115 from both sides )

a = 20

6 0
3 years ago
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
3
Svet_ta [14]

Answer:17,000

Step-by-step explanation:Add 532+150=680 then times it by 25 which equals 17,000

5 0
3 years ago
Read 2 more answers
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