The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D
Step-by-step explanation:
If two triangles are similar by SAS, then their corresponding angles are
equal and the 3rd corresponding sides have constant ratio
In the two triangles ABC and DBE:
- ∠ABC ≅ ∠DBE

Then the two triangles are similar
From similarity:
∠BAC ≅ ∠BDE
∠BCA ≅ ∠BED
∴ The missing step is ∠BAC ≅ ∠BDE
The missing step in this proof is ∠BAC ≅ ∠BDE
Learn more:
You can learn more about triangles in brainly.com/question/3451297
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Answer:
Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.
Step-by-step explanation:
11/6 is less than. 6 only goes into 11 once,, so it'd be 11/6
(x^2-3x+2)-1(3x^2-5x-1)=
x^2-3x+2-3x^2+5x+1=
x^2-3x^2-3x+5x+2+1=
-2x^2+2x+3