hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
X/y = 2 so x = 2y
z/x = 4 so z = 4x but x = 2y so z = 4(2y) = 8y
now you have
x = 2y, z = 8y
x + y + z 2y + y + 8y 11y 11
------------ = -----------------------= ------------- = ----------- = 5 1/2
x 2y 2y 2
answer
C. 5 1/2
Answer:
68 feet
Step-by-step explanation:
A square with area 289 ft² has sides √289 = 17 ft long. There are 4 of them so the perimeter is 4×17 ft = 68 feet.
Mr. Drew needs 68 feet of wood for the sides of the sandbox.
Answer:
c
Step by step explanation: Linear equations don't have exponents, so that makes option c nonlinear
