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earnstyle [38]
3 years ago
9

Please help ASAP I will mark brainlest

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

160 units.

Step-by-step explanation:

In order to find the minimum cost, we need to find the vertex of the equation since it is the lowest point of the graph. To find the vertex, we use the following equation.

x = -b/2a

In this equation, a is the coefficient of x^2 and b is the coefficient of x. So we plug in and solve.

x = -b/2a

x = -(-80)/2(.25)

x = 80/.5

x = 160

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You spin a spinner that has 15 equal-sized sections numbered 1 to 15. Find the theoretical probability of: P(odd number)
Basile [38]

Answer: The correct answer is

Step-by-step explanation:

8 0
3 years ago
The amount Lin's sister earns at her part-time job is proportional to the number
gulaghasi [49]

Answer:

y = 9.6x

Yes, y is a function of x.

x =  \frac{5}{48} y

Step-by-step explanation:

For a proportional relation, the equation is given by:

y = kx

where k is the unit rate of change.

We were told that, Lin's sister earns $9.6 per hour.

This means k=9.6.

We substitute to get:

y = 9.6x

We could rewrite this as

y(x) = 9.6x

Yes, y is a function of x.

To obtain an equation describing x as a function of y, we solve for x to get:

x =  \frac{1}{9.6} y

6 0
3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
3 years ago
What is the first step in solving the equation
Varvara68 [4.7K]

Answer:

First Step: separate x^2 from -16

Second Step: add -16/25 to the other side.

Step-by-step explanation:

x^2 - 16/25 = 0

^^ this might be easier if you separate x^2 and -16

<em>First Step-</em>

so rewrite the problem as x^2/25  -16/25 = 0

then...

<em>Second Step-</em>

add -16/25 to the other side. This makes it: x^2/25 = 16/25

<em>Continuation-</em>

Now, you can multiply 25 on both sides to cancel it out.

so you have x^2 = -16

Message me if you want to solve for x.

4 0
3 years ago
Read 2 more answers
What is the perimter of this figure?
alexira [117]

Answer:

30!

Step-by-step explanation:

Add all sides.

8 0
2 years ago
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