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3 years ago

Which equation has a solution of x = 1.5? 1 point

Mathematics

2 answers:

mario62 [17]3 years ago

5 0

Answer:

1 point

Step-by-step explanation:

lukranit [14]3 years ago

4 0

y = -2x + 3 will work if you want a linear equation

y = (2x-3)(x-3) will work if you want a quadratic

y = (2x-3)(x-3)(x+4) will work if you want a cubic

You might be interested in

0.5x-7= 0.3 solve the equation<br><br><br><br><br>

Lena [83]

Answer:

<h3> $\boxed{ \bold{ \boxed{ \sf{x = 14.6}}}}$ </h3>

Step-by-step explanation:

$\sf{0.5x - 7 = 0.3}$

Move 7 to right hand side and change it's sign

⇒ $\sf{0.5x = 0.3 + 7}$

Add the numbers

⇒ $\sf{0.5x = 7.3}$

Divide both sides of the equation by 0.5

⇒ $\sf{ \frac{0.5x}{0.5} = \frac{7.3}{0.5} }$

Calculate

⇒ $\sf{x = 14.6}$

Hope I helped!

Best regards!!

3 0

4 years ago

List the independent and dependent variables for each situation:

natulia [17]

Part (a)

Independent variable = age
Dependent variable = height

"depends on age" indicates that age is independent.

-----------------------------------
Part (b)

Independent variable = amount of sleep
Dependent variable = mood

The key word is "determines". The stuff before this word is the independent variable which affects the dependent variable.
-----------------------------------
Part (c)

Independent variable = time water has been running
dependent variable = amount of water in the tub

Time is usually the independent variable
-----------------------------------
Part (d)

Independent variable = speed
dependent variable = distance from home

-----------------------------------
Part (e)

Independent variable = amount of homework done
dependent variable = speed

This seems like an odd pairing of homework and speed. Could there be a typo? I noticed that part (f) is very similar

-----------------------------------
Part (f)

Independent variable = amount of hw that is assigned
dependent variable = amount of homework done

Like with part (a), the stuff before "depends" is the dependent variable

4 0

4 years ago

Point C And d lie on a graph of the equation y=1.3 what are the Y coordinates for each point

Vinil7 [7]

It is 2 brvsydd it’s true

6 0

3 years ago

The diagram below shows the radius of the circular opening of a drinking cup.

ss7ja [257]

Answer:

25 cm

Step-by-step explanation:

$C=2\pi r$ where r is the radius of the circle

Plug in the given radius (4 cm)

$C=2\pi (4)\\C=8\pi\\C=25$

Therefore, the circumference of the opening is approximately 25 cm.

I hope this helps!

3 0

3 years ago

A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from

Nimfa-mama [501]

Step-by-step explanation:

Let

$m_p$ = mass of the painter

$m_s$ = mass of the scaffold

$m_e$ = mass of the equipment

$T$ = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

$3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)$

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of $m_e$ . The net torque on the scaffold is then

$T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0$

Solving for T,

$9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})$

$T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]$

$\:\:\:\:= 423.3\:\text{N}$

To solve for the the mass of the equipment $m_e$ , use the value for T into Eqn(1):

$m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}$

6 0

3 years ago