2 years ago

Find the mode, median, mean and range for this set of data.

Mathematics

1 answer:

Lynna [10]2 years ago

3 0

Answer:

Step-by-step explanation:i dont know your mom

You might be interested in

Which of the following best describes a line

finlep [7]

I would answer, but you didn't give any options.

6 0

2 years ago

Read 2 more answers

PLEASE HELP 23 point

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

7 0

2 years ago

Solve the following system of equations using substitution <br> x = 4 <br> 2x + 4y = 36

DiKsa [7]

Just plug in 4 for the x

2*4 +4y =36
8+4y =36
4y =36-8
4y=28
y= 28/4
y=7

7 0

2 years ago

Read 2 more answers

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago

Someone please help! Thank you

borishaifa [10]

I think the answer would be D, but I’m not sure.

3 0

3 years ago

Read 2 more answers