Question

A lightning bolt may carry a current of 1.00 104 A for a short time. What is the resulting magnetic field 120 m from the bolt

Answer 1

Answer:

1.67 x 10^-5 Tesla

Explanation:

Current, i = 1 x 10^4 A

distance, d = 120 m

The formula for the magnetic field due to long straight current carrying conductor is given by

$B =\frac{\mu _{0}}{4\pi }\times \frac{2i}{r}$

$B =10^{-7}\times \frac{2\times 10^{4}}{120}$

B = 1.67 x 10^-5 Tesla

Answer 2

Answer:

B = 1.67 μ T

Explanation:

given,

current, I = 1 x 10⁴ A

r = 120 m

treating lightning bolt as long straight conductor

  $B=\dfrac{\mu_0I}{2\pi r}$

  $B=\dfrac{4\pi \times 10^{-7}\times 1 \times 10^4}{2\pi\times 120}$

resulting magnitude would be equal to

    B = 16.67 x 10⁻⁶ T

    B = 1.67 μ T

The resulting magnetic field is equal to B = 1.67 μ T