Use the information and diagram to answer the following question.

A pitcher hurls a 0.25kg ball around a vertical circular path of radius 0.6 m, applying a tangential force of 30N, before releas

Sever21 [200]

Thank you for posting your question here at brainly. Below is the solution:

Ke up top = 1/2*.25 *225
gain of Pot energy = .25*9.81*1.2 
work input = (1/4)(2 pi *.6)*30 

so 
sum of those 3 energies = 
(1/2)(.25)v^2

3 0

4 years ago

"A 75 kg swimmer dives horizontally off a 500 kg raft. If the diver's speed immediately after leaving the raft is 4 m/s, what is

svet-max [94.6K]

Answer:

0.6 m/s

Explanation:

Let the raft speed be v.

Given:

Mass of the swimmer (m) = 75 kg

Mass of the raft (M) = 500 kg

Speed of swimmer after leaving the raft (u) = 4 m/s

Now, the given situation can be considered a problem of conservation of total momentum before and after collision.

Momentum is the product of mass and velocity.

Here, the swimmer and raft are the bodies in collision.

So, before the collision, both the bodies were at rest. So, initial momentum is 0. Now, from conservation of momentum, the final momentum of the system must be 0 after the collision. Therefore,

Final Momentum = 0

$mu+Mv=0\\\\Mv=-mu\\\\v=-\dfrac{mu}{M}$

Plug in the given values and solve for 'v'. This gives,

$v=-\frac{75\times 4}{500}\\\\v=-\frac{300}{500}=-0.6\ m/s$

The final velocity of the raft is -0.6 m/s. Now, speed is the magnitude of velocity.

Therefore, the corresponding raft speed is 0.6 m/s.

7 0

3 years ago

A push or a pull on an object is known as a(n)

balu736 [363]

Force is a push or a pull of an object that causes the object to speed up, slow down, or stay in one place. In other words, a force is what causes an object to move. Friction and gravity are two types of forces that influence how an object moves.

Hope I can help you!

6 0

3 years ago

Read 2 more answers

What is the strength of the electric field in a region where the electric potential is constant?

Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

Therefore, a constant electric potential means that electric field is zero.

4 0

3 years ago

an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electr

Alja [10]

See attached file:
We are given the electric field equation so we input all the values we are given, eventually getting E = 51.75 N/C

3 0

3 years ago