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Inessa05 [86]
3 years ago
14

A company is evaluating a new reading program that is supposed to improve test scores. The box plots show the results of reading

tests given before and after using the program. With this data, what is the most reasonable answer to the question: Does the program improve test scores 20 pts

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

I would go with C.  

Step-by-step explanation:

Some of the students did better on the q1 and q3 area but overall the minimum and maxium are still the same amount so the effect didnt work.  The highest grade on the pretest was the same on the post test and likewise with the lowest score so the answer would be C

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Point A is located at (5, 10) and point B is located at (20, 25).
Alla [95]
Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at  a ratio of 7, thus 3:7,

\bf \left. \qquad  \right.\textit{internal division of a line segment}
\\\\\\
A(5,10)\qquad B(20,25)\qquad
\qquad 3:7
\\\\\\
\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\
-------------------------------\\\\
{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\
-------------------------------

\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)
\\\\\\
C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10}  \right)
\\\\\\
C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2}  \right)
8 0
3 years ago
75. Simplify the expression: -2x(4x^2 - 5x + 3)
Karolina [17]

-2x(4x² - 5x + 3)    Distribute/multiply -2x into (4x² - 5x + 3)

(4x²)(-2x) - (5x)(-2x) + (3)(-2x)

-8x³ + 10x² - 6x


Your answer is the 3rd option

3 0
3 years ago
The speeds of cars on a given i street we are normally distributed with a mean of 72 miles per hour and a standard deviation of
Ostrovityanka [42]

Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

Step-by-step explanation:

Let X be a random variable that represents the speed of the drivers.

Given: population mean : M = 72 miles ,

Standard deviation: s= 3.2 miles

The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:

P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278

Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.

3 0
3 years ago
Evaluate the expression when y = 5.<br> 3y2<br> 3y2 =
noname [10]

Answer:

17 is the answers to the question

4 0
2 years ago
An excavating company charges $300 an hour for the use of a backhoe and $500 an hour for the use of a bulldozer. (part of an hou
Fed [463]

We have that

Cost use of a backhoe----------------------$300 an hour

<span> Estimate for equipment rental each week---------------------$18,400</span>

Total hours operator per week--------------------------------------40

<span> 40*300</span>=$12000---------------------it is the cost per week to use a backhoe

 $12000<$18400  is ok 

<span> The maximum of hours that I can rent </span>a backhoe <span> are 40 hours, since it is the limit of the operator and it do not overcome the total budget </span>

4 0
3 years ago
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