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Inessa05 [86]
3 years ago
14

A company is evaluating a new reading program that is supposed to improve test scores. The box plots show the results of reading

tests given before and after using the program. With this data, what is the most reasonable answer to the question: Does the program improve test scores 20 pts

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

I would go with C.  

Step-by-step explanation:

Some of the students did better on the q1 and q3 area but overall the minimum and maxium are still the same amount so the effect didnt work.  The highest grade on the pretest was the same on the post test and likewise with the lowest score so the answer would be C

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140=2x+2y in standard form
Sedbober [7]

Answer:

it is in standard form

Step-by-step explanation:

your thinking of y intercept not standard

6 0
3 years ago
Jon makes a map of his neighborhood for a presentation. The scale of his map is 1 inch:125 feet, however Jon realizes that his m
kati45 [8]

Answer:

1 inch:625 feet

Explanation:

125 x 5 = 625

5 0
3 years ago
he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size
malfutka [58]

Answer:

97

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

5 0
3 years ago
Calcular en cuanto se convertira, un capital de $15,500 en 8 meses al 6.5%
dybincka [34]
En algunos bancos, cuentas de ahorro o incluso en prestamos y empeños podemos observar que se cobra un interés mensual. Esto no significa que todos los intereses deban ser así.

El periodo, es el tiempo en el que se aplica el interés, este puede ser anual, mensual, semanal, o incluso por día.
8 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
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