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kap26 [50]
4 years ago
11

In the diagram below segment DEF is shown (since all three letters are shown, they are collinear). If

Mathematics
1 answer:
monitta4 years ago
3 0

Answer:

  • x = 4

Step-by-step explanation:

<u>Given</u>

  • DE = 3x + 2, EF = x + 5, DF = 23

<u>As per segment addition postulate</u>

  • DE + EF = DF

<u>Substituting values:</u>

  • 3x + 2 + x + 5 = 23
  • 4x + 7 = 23
  • 4x = 16
  • x = 4
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Check if the following equality is true for all values of variables: (a–3c)(4c+2a)+3c(a+3c)=(2a–c)(3c+5a)–8a^2
BabaBlast [244]

Answer:

True for all values of a, b and c.

Step-by-step explanation:

(a–3c)(4c+2a)+3c(a+3c)=(2a–c)(3c+5a)–8a^2

Left side:

(a–3c)(4c+2a)+3c(a+3c)

= 4ac + 2a^2 - 12c^2 - 6ac + 3ac + 9c^2

= 2a^2 + ac - 3c^2

Right side:

(2a–c)(3c+5a)–8a^2

= 6ac + 10a^2 - 3c^2 - 5ac  - 8a^2

= 2a^2  + ac  - 3c^2.

So we see that the left side is identical to the  right side  so it is true for all values of the variables.

3 0
3 years ago
Geometry math question no Guessing and Please show work thank you
Fiesta28 [93]

Theorem

In a triangle, the measure of an exterior angle equals the sum of the measures of its two remote interior angles.

x + y = z

4n - 18 + n + 8 = 133 - 6n

5n - 10 = 133 - 6n

11n = 143

n = 13

z = 133 - 6n = 133 - 6(13) = 133 - 78 = 55

Answer: C. 55

3 0
3 years ago
Read 2 more answers
Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
4 years ago
Square root of 22 rounded to the nearest hundredth
PilotLPTM [1.2K]

Answer:

4.69

Step-by-step explanation:

6 0
3 years ago
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Solve the following equation for y<br> 1/2x+y=24<br> what is y?
Basile [38]

Answer:

y=-1/2x+24

Step-by-step explanation:

you solve for y by isolating the y on one side of the equation and the rest of the equation on the opposite side of the equal sign.

1/2x-1/2x+y=24-1/2x

y=24-1/2x

rewritten: y=-1/2x+24

5 0
3 years ago
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