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VashaNatasha [74]
4 years ago
7

If c= the number of cars in a parking lot, which algebraic expression

Mathematics
1 answer:
sveticcg [70]4 years ago
4 0

Answer:

D. C+9

Step-by-step explanation:

C represents the number of cars in the parking lot.

The number of cars increased by 9.

That means 9 plus the number of cars already available at the parking lot

That’s c + 9

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Lunna [17]
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School is making digital backups of old reels of film in its library archives the table shown approximate run Times of the films
Gemiola [76]

One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of <em>x</em> on the table given will correspond to the value of <em>y</em> on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

y=7.72(3)-29.02=-5.86_{}

Since the value of <em>y</em> is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for <em>y</em>

y=-7.52(3)^2+0.19(3)+3.26=-63.85

Since the value of <em>y</em> is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put <em>x</em> = 3 on the third equation and solve for <em>y,</em>

y=0.4(3)^2+0.79(3)-4.93=1.04

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of <em>x</em>. If x = 5, we get

y=0.4(5)^2+0.79(5)-4.93=9.02

which has a slight deviation on the given value of <em>y</em> on the table for <em>x</em> = 5. let's try for <em>x</em> = 7. We have

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and the answer has a small deviation compared to the actual value given. The other values of <em>x</em> can again be put on the equation and check their corresponding value of <em>y</em>, and the resulting values are as follows

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And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put <em>x</em> = 3 on the third equation and solve for <em>y,</em>

y=4.19(1.02)^3=4.45_{}_{}

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of <em>x</em>. If x = 5, we get

y=4.19(1.02)^5=4.63

where the answer's deviation is too large compared to the value of <em>y</em> if x = 5 on the table given.

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PLEASE HELP ASAP Please?
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Answer:

c

Step-by-step explanation:

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The ranges are as follows:

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The answer that is not in these 4 is c. y ≤ -8. y is never less than -8, so this is wrong

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

You can do it simply by just typing in the calculator 4893.75÷6.75.

But I can show my work. Picture below

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