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3 years ago

Y=-6x-1 function rule

Mathematics

1 answer:

Flauer [41]3 years ago

7 0

Answer:

Multiply by negative 6 and subtract by 1. See description for more information about this function.

Step-by-step explanation:

The function rule is to "multiply by negative 6 and subtract 1". This function would have a table values like this:

x y (x,y)

-3 y= -6(-3) - 1= 17 (-3,17)

-2 y = -6(-2) -1 = 11 (-2,11)

-1 y = -6(-1)-1 = 5 (-1,5)

0 y = -6(0)-1 = -1 (0,-1)

1 y = -6(1)-1 = -7 (1,-7)

2 y = -6(2)-1 = -13 (2,-13)

3 y = -6(3)-1 = -19 (3,-19)

Its graph would be the (x,y) points connected on a graph. See attached picture.

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Find the sum. ???? 2 0 −2 3 ???? + ????1 5 0 1 ????

julia-pushkina [17]

Answer:

$\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]$

Step-by-step explanation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]$

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$A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]$

In this case we have:

$A=\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]\\\\\\B=\left[\begin{array}{cc}1&5\\0&1\end{array}\right]$

The sum is:

$A+B=\left[\begin{array}{cc}2+1&0+5\\-2+0&3+1\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]$

The answer is:

$\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]$

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The verticles of a polygon p(0,4), q(5,4), r(5.-3) and s(0,-3). What are the perimeters of the polygon

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Answer:

Following are the responses to the given question:

Perimeter of polygon:

$PQ = 5\\\\RS = 5\\\\PR = QS=\sqrt{74} = 8.60\\\\QR = 7$

Step-by-step explanation:

In this question we calculate the perimeter of a polygon which can be defined as follows:

Using formula:

$d = \sqrt{(x _2 - x_1)^2 + (y_2 - y_1)^2}$

When vertices are:

$P ( 0 , 4) \\\\Q(5 , 4)$

$x_1 = 0\\\\y_1 = 4\\\\x_2 = 5\\\\y_2 = 4\\\\PQ = \sqrt{( 5 - 0)^2 + ( 4 - 4)^2}\\\\= \sqrt{5^2 + 0^2}\\\\= \sqrt{25}\\\\= 5$

$R( 5 , -3) and S ( 0 , -3)x_1 = 5y_1 = -3x_2 = 0\\y_2 = -3\\RS = \sqrt{ ( 0 - 5)^2 + ( -3 - (-3))^2}\\= \sqrt{( -5)^2 + ( -3 + 3)^2}\\= \sqrt{ 25 + 0}\\= \sqrt{25}\\= 5\\P( 0 , 4)\ and\ R (5 , -3)\\x_1 = 0\\y_1 = 4\\x_2 = 5\\y_2 = -3\\PR = \sqrt{( 5 - 0)^2 + ( -3 - 4)^2}\\= \sqrt{5^2 + (-7)^2}\\= \sqrt{ 25 + 49}\\= \sqrt{74}\\= 8.60\\$

$Q ( 5 , 4) \ and \ S(0 ,-3)\\x_1 = 5\\y_1 = 4\\x_2 = 0\\y_2 = -3\\QS =\sqrt{ ( 0 - 5)^2 + ( -3 - 4)^2}\\= \sqrt{-5^2 + -7^2}\\= \sqrt{25 + 49}\\= \sqrt{74}\\= 8.60$

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