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tensa zangetsu [6.8K]
4 years ago
14

How much orange juice at 42¢ a liter should be mixed with grapefruit juice worth 32¢ a liter to make 200 liters of a mixture wor

th 36¢ a liter?
If x represents the amount of orange juice used, then which of the following expressions represents the total cost of the grapefruit juice used?

0.32x
0.32(200 - x)
0.32(x + 200)
Mathematics
2 answers:
Leno4ka [110]4 years ago
5 0

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

Cost of grapefruit per liter = 32

Cost of orange juice per liter= 42

Total quantity of mixture = 200 liters

Let the quantity of orange juice be x

So, the quantity of grapefruit juice be 200-x

So, the total cost of the grapefruit juice used will be

0.32(200-x)

According to question,

0.32(200-x)+0.42x=200\times 0.36\\\\64-0.32x+0.42x=72\\\\0.42x-0.32x=72-64\\\\0.1x=8\\\\x=80\\\\\text{ So, the amount of grapefruit juice will be }=200-80=120

Hence, Second option is correct.


pickupchik [31]4 years ago
5 0
X = the amount of orange juice that still has to be mixed


If it says that the total of the juice will be 200 liters, then (200-x) = the amount of grapefruit juice that still needs to be mixed.


The grapefruit juice amount would be: 200 - 80 = 120 liters




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Solve.
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The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6

\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
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