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3 years ago

Does anyone know how to do this?

Mathematics

1 answer:

docker41 [41]3 years ago

3 0

Answer:

bone or necklace

Step-by-step explanation:

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Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori

inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = $\dfrac{1}{3}(10p+q)$

= $\dfrac{10p+q}{3}$

thrice more than that will be = $\dfrac{10p+q}{3} + 3$

∴

$\dfrac{10p+q}{3} + 3 = 10q+p$

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0

3 years ago

HELP ME PLEASEEEEEEEEEEEEE

zepelin [54]

Answer:

Step-by-step explanation:

Brₐinliest plz close to leveling up

3 0

2 years ago

Read 2 more answers

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

3 years ago

Read 2 more answers

I need help ASAP (get brainliest)

maria [59]

Its B trust me i know

3 0

3 years ago

Which answer shows a correct slope calculation?

Sliva [168]

If the lines with those given slopes go trough 2 points then

A) is correct if the points are (6, 0) and (0, 3)

B) is correct if the points are (0, 0) and (-6, 3)

C) is correct if the points are (-6, 0) and (0, 3)

5 0

3 years ago