All categories

3 years ago

Formula is area equals 1/2bh for triangle

Mathematics

2 answers:

3241004551 [841]3 years ago

8 0

We can use the pythagorean theorem to find the distance between the two cities. This theorem is $a^2 + b^2 = c^2$ where a and b are the legs of the triangle and c is the hypotenuse of the trinagle. Therefore:

$14^2 + b^2 = 50^2$

$196 + b^2 = 2500$

$b^2 = 2304$

$b = \sqrt{2304}$

$b = 48$

Thus, the answer is B, 48 miles.

Dmitry [639]3 years ago

5 0

Your answer is B. 48 miles. This is because the formula a² + b² = c² can be used to find the hypotenuse, which means the formula
a² - c² = b² can be used to find the side of a right triangle. This means that we can do
50² - 14² = 2304, and then we square root it to get 48.
I hope this helps!

You might be interested in

Mira bought $500 of Freerange Wireless stock in January of 1998. The value of the stock is expected to

Alexus [3.1K]

Answer:

2002

Step-by-step explanation:

The main topic of the question is compound interest.

If the percentage increase is 7.5%. Then the decimal multiplier would be 1.075. The 1 in front of the decimal represents the increase. 7.5 in decimal form is 0.075, so we just add the two together to get our decimal multiplier.

Now we do trial and error to see when we reach $700. After we get at least $700, we count how many times we multiplied $500 by the decimal multiplier and onwards to figure out the number of years it took and then add that to 1997. We add it to 1997 because the cost of the Freerange Wireless stock must have also been $500 at the end of 1997. The beginning of 1998 is the same as the end of 1997.

1) 500 x 1.075 = $537.50

2) 537.50 x 1.075 = $577.81

3) 577.81 x 1.075 = $621.15

4) 621.15 x 1.075 = $667.74

5) 667.74 x 1.075 = $717.8205

1997 + 5 = 2002

The value of Mira's stock will reach $700 by the end of 2002 because if we know that she used $500 at the beginning of 1998, that also means the cost of the Freerange Wireless stock was $500 at the end of 1997.

I hope this helps.

3 0

4 years ago

Need help with this please

Annette [7]

First, are you really familiar with the graph of y = [x]? If so, your answer choices move that graph up or down.

A. Move the graph of y=[x] UP 3 units
B. Move the graph UP 1 unit
C. Move the graph DOWN 1 unit
D. Move the graph DOWN 3 units

The graph you're given on the problem screen is not a very good one, I think. Would it help to draw y = [x] on a piece of graph paper where one square = 1 unit? The graph you're shown has one square = 2 units, which could lead to some confusion.

So, draw the graph of y = [x], then figure out which way the graph was moved -- and how far -- to get the graph in the problem.

Here is a link to a YouTube video that might help a lot.
https://youtu.be/UQ3a2QH_-GU

5 0

4 years ago

| 2. On rectangle ABCD below, if A is located at

vovangra [49]

Answer:

-2

Step-by-step explanation:

Given that:

A = (3, 4) ; B = (7, 6)

In triangle ABCD, AB and BC are Perpendicular lines :

Slope AB = Rise / Run = (y2 - y1) / (x2 - x1)

y2 = 6 ; y1 = 4 ; x2 = 7 ; x1 = 3