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Illusion [34]
3 years ago
13

can someone help me, Just the answer don’t worry about explaining everything, Im really bad on Math :(

Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

a. -2 b. -2 c. -1 d. 4 e. -3 f. 0

Step-by-step explanation:

The average rate of change formula is:

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}

a.  

We need to find the rate of change for x = -3 to x = -2 so we look on the graph to find y.

At x = -3 it look like y = 0  so

x_{1} = -3

y_{1} = 0

At x = -2 it looks like y = 2

x_{2} = -2

y_{2} = 2

Now we can just plug everything in to the rate of change formula.

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{2- 0}{-3-(-2)} = \frac{2- 0}{-3+2} = \frac{2}{-1} = -2

So for a. our rate of chage for the given interval is -2

b.

Now that you have the formula we don't need to explain each time.

x_{1} = -2

y_{1} = 2

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4- 2}{1-(-2)} = \frac{-4-2}{1+2} = \frac{-6}{3} = -2

c.

x_{1} = 0

y_{1} = -3

x_{2} = 1

y_{2} = - 4

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-4-(-3)}{1-0} = \frac{-4 + 3}{1-0} = \frac{-1}{1} = -1

d.

x_{1} = 1

y_{1} = -4

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0 - (-4)}{2-1} = \frac{0 + 4}{2-1} = \frac{4}{1} = 4

e.

x_{1} = -1

y_{1} = 0

x_{2} = 0

y_{2} = -3

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{-3- 0}{0-(-1)} = \frac{-3- 0}{0+1} = \frac{-3}{1} = -3

f.

x_{1} = -1

y_{1} = 0

x_{2} = 2

y_{2} = 0

\frac{y_{2}- y_{1}}{x_{2}-x_{1}}  = \frac{0- 0}{2-(-1)} = \frac{0- 0}{2+1} = \frac{0}{3} = 0

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