All categories

3 years ago

The perimeter of a square tent is 82 feet. Find the area of the ground which the tent will cover

Mathematics

1 answer:

melamori03 [73]3 years ago

7 0

Answer:

420.25

Step-by-step explanation:

If the perimeter is 82, each side is 20.5. Then you do 20.5 x 20.5 to get 420.25.

You might be interested in

Which of the following methods of timekeeping is the least precise?

Westkost [7]

It’s c counting your heartbeats

8 0

3 years ago

What else would need to be congruent to show that ABC = PQR by sss

Katen [24]

Ab=pq
qr= bc
and so on

7 0

2 years ago

9328553.99 multiply by 10 the decimal will move one place to the left or two places to the left or one place to the right or two

VARVARA [1.3K]

93285539.900000000000

7 0

3 years ago

!!!The volume of the given figure is______!!!!

choli [55]

Answer:

284.837734 ft^3 rounded up to 284.84 ft^3

Step-by-step explanation:

Cylinder Volume: pi*r^2h

pi*4^2*4=201.06193

Cone Volume: pi*r^2*(h/3)

pi*4^2*(5/3)=83.7758041

201.06193+83.7758041=284.837734

284.837734 ft^3

7 0

3 years ago

Match the y-coordinate with the given x-coordinate for the equation y = log10x.

Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:

$For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.$

We know that the equations is:

$y=log(10x)$

So let's solve each case:

Case 1

$x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}$

Case 2

$x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}$

Case 3

$x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}$

Case 4

$x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}$

Case 5

$x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}$

5 0

3 years ago

Read 2 more answers