Answer:(1,1)
Step-by-step explanation:
y=4.5x
x=y/4.5
put value of x
y=4.5(y/4.5)
y=y
C. 2 + (–3); –1 is the answer
<h2>
Question:</h2>
Find k if (x+1) is a factor of 2x³ + kx² + 1
<h2>
Answer:</h2>
k = 1
<h2>
Step-by-step explanation:</h2>
The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.
<em>This is because;</em>
i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.
ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e
=> (-3)² - 9
=> (9) - 9 = 0
Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.
<em><u>From the question</u></em>
Given polynomial: 2x³ + kx² + 1
Given factor: x + 1.
Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e
2(-1)³ + k(-1)² + 1 = 0
2(-1) + k(1) + 1 = 0
-2 + k + 1 = 0
k - 1 = 0
k = 1
Therefore the value of k is 1.
y = -1 + 3/8x
2x - 5y = 6
Substitute the first equation into the second equation, since y is already by itself.
2x - 5(-1 + 3/8x) = 6
2x + 5 - 15/8x = 6
2x - 15/8x = 1
16/8x - 15/8x = 1
1/8x = 1 Multiply 8 on both sides to get x by itself
x = 8
Plug x into either of the equations.
y = -1 + 3/8(8)
y = -1 + 3
y = 2
2(8) - 5y = 6
16 - 5y = 6
-5y = -10
y = 2
(8,2)
