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3 years ago

15

Isaac has 80 cards and Jeremy has 40 cards. They decide to combine their cards, and then split them equally. How many cards will

each person receive

1 answer:

wlad13 [49]3 years ago

5 0

You would do 80+40 which is 120 then you would do 120 divided by 2 which is 60 so therefore each person would get 60 cards.

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Assume that the probability of any newborn baby being a boyboy is one half 1 2 and that all births are independent. if a family

Arte-miy333 [17]

I think the correct answer should be 1/8 or 1:8

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2 years ago

Identity each pair of angles as complementary, supplementary, or neither.

CaHeK987 [17]

Answer:

Neither

Supplementary

Supplementary

Step-by-step explanation:

1) 90 + 43 = 133

Since this value does not equate to 90 or 180. The answer is Neither

2) 61 + 119 = 180

Since the answer equates to 180. The answer is Supplementary

3) 90 + 90 = 180

Since the answer equates to 180. The answer is Supplementary

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2 years ago

Jessie estimated the weight of his cat to be 12 pounds. The actual weight of the cat is 15 pounds.

Veronika [31]

3 times 100 divided by 15 gives us 20%

6 0

2 years ago

Read 2 more answers

klasskru [66]

19.2 * 10⁸ minutes.

60 minutes = 1 hour.

19.2 * 10⁸ minutes = (19.2 * 10⁸) / 60 hour

= 32 000 000 = 3.2 * 10⁷ hours

= <span>D. 3.200 × 10^7 h</span>

3 0

3 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

<u>Given:</u>

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

<u>Calculate:</u>

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0

1 year ago