Answer:
1/3 < 2/5 < 3/7 < 5/8 < 3/4
Step-by-step explanation:
Using the given inputs:
3/4 5/8 3/7 1/3 2/5
The least common denominator (LCD) is: 840.
Rewriting as equivalent fractions with the LCD:
3/4= 630/840
5/8= 525/840
3/7= 360/840
1/3= 280/840
2/5= 336/840
Sorting this by the numerators of the equivalent fractions in order from least to greatest:
1/3= 280/840= < 2/5= 336/840= < 3/7= 360/840= < 5/8= 525/840= < 3/4
= 630/840
Therefore, the sorted inputs in order from least to greatest is:
1/3 < 2/5 < 3/7 < 5/8 < 3/4
Hopes this helps!
Have a good evening! :)
Answer:
13.7 ft^2
Step-by-step explanation:
1. Find the radius of the semicircle by dividing the diameter by 2 to get 1.8
2. Find the area of the semicircle. Do this by substituting the equation to find the area of a semicircle with the numbers given and solving. 3.14(1.8^2)/2 = 5.0868
3. Find the area of the triangle. Do this by substituting the equation to find the area of a semicircle with the numbers given and solving. 1/2(3.6*4.8) = 8.64
4. Add both your numbers together to get 13.7268
5. Round to the nearest 10th to get 13.7 ft^2
Answer:
There is 8 vertices!
Step-by-step explanation:
They are just the points of the cube!
Hope this helps!
Step-by-step explanation:
Use COS method (Cos Angle = adjacent/hypotenuse)
given adjacent = 14 ft
hypotenuse = 67 ft
Answer:
1. S.A. = 4350 cm²
2. S.A. = 864 cm²
3. S.A. = 240 cm²
4. S.A. = 224 m²
5. S.A. = 301.6 in.²
6. S.A. = 6,082.1 cm²
7. S.A. = 923.6 in.²
Step-by-step explanation:
1. Surface area of the rectangular prism = 2(LW + LH + WH)
L = 45 cm
W = 25 cm
H = 15 cm
S.A. = 2(45*25 + 45*15 + 25*15)
S.A. = 4350 m²
2. Surface area of the cube = 6a²
a = 12 cm
S.A. = 6(12²)
S.A. = 864 cm²
3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H
b = 4 cm
h = 6 cm
s1 = 4 cm
s2 = 7 cm
s3 = 7 cm
H = 12 cm
Plug in the values
S.A. = 4*6 + (4 + 7 + 7)*12
S.A. = 24 + (18)*12
S.A. = 24 + 216
S.A. = 240 cm²
4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)
S.A. = (8*8) + 4[(8*10)/2]
S.A. = 64 + 4(40)
S.A. = 64 + 160
S.A. = 224 cm²
5. Surface area of the cone = πrl + πr²
r = 6 in.
l = 10 in.
S.A. = π*6*10 + π*r²
S.A. = 60π + 36π
S.A. = 301.592895
S.A. = 301.6 in.² (nearest tenth)
6. Surface area of the sphere = 4πr²
r = 22 cm
S.A. = 4*π*22²
S.A. = 1,936π
S.A. = 6,082.1 cm² (nearest tenth)
7. Surface area of the cylinder = 2πrh + 2πr²
r = 7 in.
h = 14 in.
S.A. = 2*π*7*14 + 2*π*7²
S.A. = 923.6 in.² (nearest tenth)
