Ammonia reacts with copper(ll)oxide to give nitrogen gas, copper and steam. Balance the equation. If 18.1g of ammonia is reacted
with 90.4g of coope(ll)oxide,how many moles of each reacts?,and how many grams of nitrogen are formed?
1 answer:
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Answer:- Volume decreases by a factor of 1.15.
Solution:- At constant pressure, volume of the gas is directly proportional to the the kelvin temperature.
The equation is written as:
where, is the volume at initial temperature
and
is the volume at final temperature
.
Temperature must be in kelvins. So, let's convert both the temperatures to kelvin.
To convert degree C to kelvin we add 273.
So, = 100 + 273 = 373 K
= 50 + 273 = 323 K
The equation could also be written as:-
= 1.15
From here we could say that the volume decreases by a factor of 1.15.
For example if the initial volume is 1 L then final volume
will be
that is 0.87 L.